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g100num [7]
4 years ago
10

How can so many different substances in the world be made of so few elements?

Chemistry
1 answer:
Mrrafil [7]4 years ago
7 0
Matematically speaking, maybe because:
The number of substances = number of elements + number of different combinations of those elements
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ElenaW [278]
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5 0
3 years ago
The pH of a 1.4M solution of barbituric acid HC4H3N2O3 is measured to be 1.93. Calculate the acid dissociation constant Ka of ba
tiny-mole [99]

Answer:

9.8 × 10⁻⁵

Explanation:

Let's consider the acid dissociation of barbituric acid.

HC₄H₃N₂O₃(aq) ⇄ C₄H₃N₂O₃⁻(aq) + H⁺(aq)

The pH is 1.93. We can find the concentration of H⁺.

pH = -log [H⁺]

[H⁺] = antilog -pH = antilog -1.93 = 0.0117 M

The concentration of the acid (Ca) is 1.4 M. We can fidn the acid dissociation constant (Ka) using the following expression.

[H⁺] = √(Ca × Ka)

[H⁺]² = Ca × Ka

Ka = [H⁺]² / Ca

Ka = (0.0117)² / 1.4

Ka = 9.8 × 10⁻⁵

6 0
4 years ago
By definition, what type of fatty acid has double bonds?.
Doss [256]

Answer:

Fatty acids are comprised of hydrocarbon chains terminating with carboxylic acid groups. Fatty acids and their associated derivatives are the primary components of lipids. The length and degree of saturation of the hydrocarbon chain is highly variable between each fatty acid, and dictates the associated physical properties (e.g., melting point and fluidity). Moreover, fatty acids are responsible for the hydrophobic properties (insoluble in water) exhibited by lipids.

Function of Fatty Acids

Explanation:

6 0
2 years ago
Match each term to a correct example from the chemical equation: 2A + B2 → 2AB.
kari74 [83]

Explanation:

The given equation is as follows.

       2A + B_{2} \rightarrow 2AB

Reactants are the species present on the left hand side of a chemical equation.

Products are the species present on the right hand side of a chemical equation.

Whereas coefficients are the number present in front of formulas.

Therefore, in the given reaction equation, matched terms are as follows.

  • Reactant is B_{2}
  • Product is AB.
  • Coefficient is 2.  
3 0
3 years ago
In the electron configuration [ar]4s23d104p4, which are valence electrons?
Zigmanuir [339]
2,10,4 are valence electrons
7 0
4 years ago
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