A solid-state<span> phase </span>transformation<span> occurs when the interface between two grains that are chemically or structurally different moves.</span>
D is the answer. You cannot say that anyone is good at anything because it doesn't say that. And they were surveying the class of 2010
For this problem we can use half-life formula and radioactive decay formula.
Half-life formula,
t1/2 = ln 2 / λ
where, t1/2 is half-life and λ is radioactive decay constant.
t1/2 = 8.04 days
Hence,
8.04 days = ln 2 / λ
λ = ln 2 / 8.04 days
Radioactive decay law,
Nt = No e∧(-λt)
where, Nt is amount of compound at t time, No is amount of compound at t = 0 time, t is time taken to decay and λ is radioactive decay constant.
Nt = ?
No = 1.53 mg
λ = ln 2 / 8.04 days = 0.693 / 8.04 days
t = 13.0 days
By substituting,
Nt = 1.53 mg e∧((-0.693/8.04 days) x 13.0 days))
Nt = 0.4989 mg = 0.0.499 mg
Hence, mass of remaining sample after 13.0 days = 0.499 mg
The answer is "e"
Answer:
Explanation:
Hello,
In this case, for the given reaction, the equilibrium constant turns out:
![Keq=\frac{[B]}{[A]}=\frac{0.5M}{1.5M} =1/3](https://tex.z-dn.net/?f=Keq%3D%5Cfrac%7B%5BB%5D%7D%7B%5BA%5D%7D%3D%5Cfrac%7B0.5M%7D%7B1.5M%7D%20%3D1%2F3)
Nonetheless, we are asked for the reverse equilibrium constant that is:
Which is greater than one.
In such a way, the Gibbs free energy turns out:
Now, since the reverse equilibrium constant is greater than zero its natural logarithm is positive, therefore with the initial minus, the Gibbs free energy is less than zero, that is, negative.
