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kumpel [21]
3 years ago
10

A regular hexagon ABCDEF is shown……work out the size of angle x

Mathematics
2 answers:
denpristay [2]3 years ago
7 0

Answer:

x=30

Step-by-step explanation:

Since this a regular hexagon, each angle measure is congruent.

A hexagon interior angles add to be

({6 - 2}) \times 180 = 720

However, in the triangle, only part of angle b and angle f is in the triangle. However angle a is fully in the triangle so

Angle A=120.

So using the triangle interior theorem, angle b and f must add up to 180.

120 + x + y = 180

However, since this is a regular hexagon, the sides are equal so this is a isoceles triangle.

Using the base isoceles triangle theorem, angle b and angle f of the triangle must be equal so

x = y

120 + 2x = 180

2x = 60

x = 30

vredina [299]3 years ago
4 0
The correct answer should be x=30
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Step-by-step explanation:

Point slope form and slope-intercept form are both ways of expressing the equation of a straight line. Point slope form emphasizes the slope and ANY point on the line. Slope intercept form just shows the slope and the y-intercept of a line

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161/495

Step-by-step explanation:

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2 years ago
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6 0
3 years ago
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The product of two consecutive positive integers is 29 more than their sum. Find the integers
Rina8888 [55]
The consecutive positive integers would be: x and (x+1),
We would have to solve the following equation to find these numbers:
x(x+1)-[x+(x+1)]=29
x²+x-2x-1=29
x²-x-30=0
x=[1⁺₋√(1+120)]/2
x=(1⁺₋11)/2
We have two possible solutions:
x₁=(1-11)/2=-5    then: (x+1)=-5+1=-4  This is not the solution.
x₂=(1+11)/2=6    then: (x+1)=6+1=7    This solution is right.

Answer: the numbers would be 6 and 7. 
7 0
3 years ago
How to find restrictions for x??<br> 3. F(x)=2 sqrt x-4
stealth61 [152]

Answer:

  1. none
  2. none
  3. x ≥ 4

Step-by-step explanation:

The restrictions placed on the independent variable in a function are those necessary to ensure that the function is defined for all allowed values of that variable.

In the graphs of problems 1) and 2), we see that the functions are defined for all values of x, so there are no restrictions.

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3. For the function ...

  f(x)=2\sqrt{x-4}

the value under the radical cannot be negative. The square root function is not defined for negative values, so the restriction is ...

  x -4 ≥ 0

  x ≥ 4 . . . . . . . add 4 to both sides of the inequality

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3 years ago
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