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2 years ago

Does the graph in Exercise 33 have a Hamilton path? If

Mathematics

1 answer:

Ainat [17]2 years ago

5 0

;

Answer:

there is a graph first step to but I cannot draw it on here but you already have your answer without Step 2

Step-by-step explanation:

a simple path in a graph G that passes through every vertex exactly once is called a path . the graph G has no past because any past containing all vertices must contain one of the edges (e, c) (d, f ) and (B, G) move than once .

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Step-by-step explanation:

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netineya [11]

Answer:

B. x = -1 ± i

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Algebra I

Standard Form: ax² + bx + c = 0
Factoring
Quadratic Formula: $\displaystyle x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$

Algebra II

Imaginary Numbers: √-1 = i

Step-by-step explanation:

Step 1: Define

x² + 2x = -2

Step 2: Identify Variables

Rewrite Quadratic in Standard Form [Addition Property of Equality]: x² + 2x + 2 = 0
Break up Quadratic: a = 1, b = 2, c = 2

Step 3: Solve for x

Substitute in variables [Quadratic Formula]: $\displaystyle x=\frac{-2 \pm \sqrt{2^2-4(1)(2)}}{2(1)}$
[√Radical] Evaluate exponents: $\displaystyle x=\frac{-2 \pm \sqrt{4-4(1)(2)}}{2(1)}$
Multiply: $\displaystyle x=\frac{-2 \pm \sqrt{4-8}}{2}$
[√Radical] Subtract: $\displaystyle x=\frac{-2 \pm \sqrt{-4}}{2}$
[√Radical] Factor: $\displaystyle x=\frac{-2 \pm \sqrt{-1}\sqrt{4}}{2}$
[√Radicals] Simplify: $\displaystyle x=\frac{-2 \pm 2i}{2}$
Factor: $\displaystyle x=\frac{2(-1 \pm i)}{2}$
Divide: $\displaystyle x = -1 \pm i$

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3 years ago