Answer:
f(4) is 6,520 greater than g(4)
Step-by-step explanation:
<span>1. Let t = time in years, with t = 0 representing the year 2005. Let f(t) = the number of students enrolled at the private school and g(t) = the number of students enrolled at the public school. Create the two functions to represent the situation.
f(t) = 85 + 18t </span>⇒ y = 85 + 18x<span>
g(t) = 95 + 15t </span>⇒ y = 95 + 15x
y = y
85 + 18x = 95 + 15x
18x - 15x = 95 - 85
3x = 10
x = 10/3
x = 3 1/3
y = 85 +18(10/3) = 85 + 180/3 = 85 + 60 = 145
y = 95 + 15(10/3) = 95 + 150/3 = 95 + 50 = 145
x = 10/3 or 3 1/3
y = 145
Yes, they're equivalent values.
Answer:
42 child and 70 adult
Step-by-step explanation:
Let a = number of adult tickets
c = number of child tickets
a+c = 112
2.25a + 1.75c = 231
Solve the first equation for a
a = 112-c
Substitute this into the second equation
2.25(112-c) + 1.75c = 231
Distribute
252 - 2.25c +1.75c = 231
Combine like terms
252 -.5c = 231
Subtract 252 from each side
252-252 -.5c = 231-252
-.5c = -21
Divide each side by -.5
-.5c/-.5 = -21/ -.5
c = 42
Now can find a
a = 112-c
a = 112-42
a = 70