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natulia [17]
3 years ago
5

Does the graph in Exercise 33 have a Hamilton path? If

Mathematics
1 answer:
Ainat [17]3 years ago
5 0

;

Answer:

there is a graph first step to but I cannot draw it on here but you already have your answer without Step 2

Step-by-step explanation:

a simple path in a graph G that passes through every vertex exactly once is called a path . the graph G has no past because any past containing all vertices must contain one of the edges (e, c) (d, f ) and (B, G) move than once .

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Ok so here's a trick king Henry doesn't usually drink chocolate milk or king Henry dabs under dogs calling mom and here's what it will look like the pic and then u have to convert them so 8 liters converting into blank dL so u put a x over the letter L and u don't see that. u see the big U well that means gram liter and meter so u put a x over top of that and now u want to go to the d so now u go just to the d NOT da and ur gonna scoop when ur done scooping them u put a dot where u ended on top of that letter now u get ur first number or what one u started with so I did 8L so I get 8 and since there is no decimal u put it at the end and now I'll scoop and since ur getting smaller u move the decimal to the left (cause left is less) and u get .8 and that's how u do that if u need help with the other ones just let me know and I'll help u

3 0
3 years ago
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I’ve been trying to figure this out all day and still can’t seem to figure it out
Marat540 [252]

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3 0
3 years ago
Graph the following inequality. Then click to show the correct graph.<br><br><br>3x - 2y ≤ 6
max2010maxim [7]

Answer:

We want to graph the inequality:

3x - 2y ≤ 6

The first step is to write this as a linear equation, to do it, we can isolate y in one side of the inequality.

3x  ≤ 6 + 2y

3x - 6  ≤ 2y

(3/2)x  - 6/2  ≤ y

(3/2)x  - 3  ≤ y

or:

y ≥ (3/2)x  - 3

Because we have the symbol ≥

The points on the line are solutions, then the first part is to graph the line:

y = (3/2)*x - 3

Next, we have:

y equal to or larger than  (3/2)*x - 3

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The graph can be seen below.

3 0
3 years ago
Find the four rational numbers and irrational numbers between 2/5 and 5/6
Savatey [412]
The four?

Of course there are an infinite number of rationals between any two different real numbers, as well as an even bigger infinite number of irrationals.

The average will be between the numbers:

\frac 1 2 (\frac 2 5 + \frac 5 6) = \dfrac{37}{60}

That's a lot of work to get a number in between.  We can just see

\frac 1 2
is between the two numbers.

The mediant, or freshman addition, will always be in between:

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2/5=.4 and 5/6 is about .83, so

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To get irrationals we could just add a teeny irrational to the ones we just generated, like \frac{6}{10} + \frac{\pi}{100}

We could just change that denominator a bit and get as many as we like.

But let's get some square roots.  The geometric mean will be between

\sqrt{ \dfrac 2 5 \cdot \dfrac 5 6 } = \dfrac{1}{\sqrt{3}}&#10;

That's the tangent from one of trig's biggest cliches, but I digress.  It's in between.

While we're on trig cliches, 

\dfrac{1}{\sqrt{2}}

is in between as well.

Keeping with the trig theme, also in between are

\dfrac{\pi} 6

and

\dfrac{\pi}{4}


the angles associated with the some of the above trig function values.

We could obviously go on as long as we cared to.



7 0
3 years ago
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