First there are many ways to approach this problem. The simplest and most direct in my opinion is this approach:
vf^2=v1^2+2ad
so when the height reaches a maximum of 35m the velocity is zero for a split second before starting to fall. So we set vf=0 and solve for v1.
v1=sqrt(2gd)=sqrt(2*9.8*35)= 26.2m/s
for initial velocity needed to reach 35m height.
Any questions please ask!
Answer: The mass of 0.5 mole of element ab is 81.67 g.
Explanation:
According to the mole concept, 1 mole of a substance contains . As, the mass of atoms is 0.49 g.
So,
Therefore, mass of 1 mole =
= 163.33 g/mol
Hence, mass of 0.5 mole of ab element is calculated as follows.
= 81.67 g
Therefore, the mass of 0.5 mole of element ab is 81.67 g.
First, let us assign the variables
y = 0.90 m, x= 15 m,
= 2.80 m
s= required
The vertical component of the trajectory is in uniformly accelerated motion. The equation is:
, while the horizontal component is
. Also,
since the object starts from rest (with respect to the downward motion). a is negative because it is moving downwards (a = -9.81 m/s^2). Substituting,
The magnitude of v0, which is speed (s), is equal to 24.1 m/s
The manipulated variable is changed by the responding variable
Answer:
The sound intensity of source #2 is 38.3 W/m²
Explanation:
Given;
sound intensity of source #1, I₁ = 38.3 W/m²
sound intensity of source #2, I₂ = 2.6 dB greater than 38.3 W/m²
To determine he sound intensity of source #2 in W/m², we must convert 2.6 dB to sound intensity in W/m².
Thus, sound intensity of source #2 = 38.3 W/m² + 1.8197 x 10⁻¹² W/m² = 38.3 W/m²
Therefore, the sound intensity of source #2 is 38.3 W/m²