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Tom [10]
3 years ago
9

a force is something that causes change in motion . what provides the force that made the cart speed up brainly/

Physics
1 answer:
Maurinko [17]3 years ago
4 0

Answer:

the unbalanced force

Explanation:

An unbalance forces are defined as the forces which causes a change in the speed or velocity of a moving object. A force causes a change in the motion of a body and an unbalanced force causes the body to change its velocity and speed or a change in its direction.

An unbalanced force will start movement in a static object or it can cause to speed up the moving object or it can cause to stop the moving object.

Thus an unbalanced force causes the cart to speed up.

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harkovskaia [24]
So we want to know what is the magnitude of the horizontal component of acceleration ah if we know that the overall acceleration a=12 m/s^2 and the angle of overall acceleration and the horizontal acceleration is α=50°. We know that ah=a*cosα. So now it isn't hard to get the horizontal component: ah=12*cos50=12*0.64=7.71 m/s^2. So the correct answer is ah=7.71 m/s^2. 
6 0
4 years ago
A model rocket is launched with an initial upward velocity of.
REY [17]

Answer:
A model rocket is launched with an initial upward velocity of 215 ft/s.

Explanation:

3 0
2 years ago
A uniformly charged ring of radius 10.0 cm has a total charge of 71.0 μC. Find the electric field on the axis of the ring at the
oee [108]

Answer:

General Expression: E = kql/(l² + r²)^(3/2)

(a) 6.3 MN/C

(b) 22.8 MN/C

(c) 6.1 MN/C

(d) 0.63 MN/C

Explanation:

The general expression for electric field along axis of a uniformly charged ring is:

<u>E = kqL/(L² + r²)^(3/2)</u>

where,

E = Electric Field Strength = ?

k = Coulomb's Constant = 9 x 10⁹ N.m²/C²

q = Total Charge = 71 μC = 71 x 10⁻⁶ C

L = Distance from center on axis

r = radius of ring = 10 cm = 0.1 m

(a)

L = 1 cm = 0.01 m

Therefore,

E = (9 x 10⁹ N.m²/C²)(71 x 10⁻⁶ C)(0.01 m)/[(0.01 m)² + (0.1 m)²]^(3/2)

E = (6390 N.m³/C)/(0.00101 m³)

<u>E =  6.3 x 10⁶ N/C = 6.3 MN/C</u>

<u></u>

(b)

L = 5 cm = 0.05 m

Therefore,

E = (9 x 10⁹ N.m²/C²)(71 x 10⁻⁶ C)(0.05 m)/[(0.05 m)² + (0.1 m)²]^(3/2)

E = (31950 N.m³/C)/(0.00139 m³)

<u>E =  22.8 x 10⁶ N/C = 27.4 MN/C</u>

<u></u>

(c)

L = 30 cm = 0.3 m

Therefore,

E = (9 x 10⁹ N.m²/C²)(71 x 10⁻⁶ C)(0.3 m)/[(0.3 m)² + (0.1 m)²]^(3/2)

E = (191700 N.m³/C)/(0.03162 m³)

<u>E =  6.1 x 10⁶ N/C = 6.1 MN/C</u>

<u></u>

(d)

L = 100 cm = 1 m

Therefore,

E = (9 x 10⁹ N.m²/C²)(71 x 10⁻⁶ C)(1 m)/[(1 m)² + (0.1 m)²]^(3/2)

E = (639000 N.m³/C)/(1.015 m³)

<u>E =  0.63 x 10⁶ N/C = 0.63 MN/C</u>

8 0
3 years ago
How fast would you have to jump off the ground in order to jump at least 10 meters in the air?
ivanzaharov [21]

Answer:

30.5

Explanation:

because you will basically have to be like flash

3 0
4 years ago
When a chemical equation contains the same number of atoms on both sides, the equation is balanced.
andreyandreev [35.5K]

<u>Answer:</u>

True.

The equation is balanced.

<u>Explanation:</u>

A balanced equation of any particular reaction is often identified when the significant  total number of atoms in each of the  significant elements present in the reactant side  often quoted as the left side is identically same as the number of atoms present in the adjacent side which is the product side also known as right side of the present reaction.  Hence it generally implies for a balanced equation to be, the number of moles on one  side of the reactant side  as well as the product side should also be similar i.e equal.

Example

Here,

No of atoms present in reactant side = 2

No of atoms present in product side= 2

Therefore, Atoms present in the reactant side= atoms present in the  product side

Hence, the equation mentioned above is chemically balanced  on both sides.

3 0
3 years ago
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