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Sloan [31]
3 years ago
6

Pls explain why

Physics
1 answer:
Zinaida [17]3 years ago
5 0

Answer:

<em>The slower car takes 24 more minutes to reach its destination.</em>

Explanation:

<u>Constant speed motion </u>

An object moves at constant speed if the ratio of the distance traveled by the time taken is constant.

Expressed in a simple equation, we have:

\displaystyle v=\frac{d}{t}

Where  

v = Speed of the object

d = Distance traveled

t = Time taken to travel d.

From the equation above, we can solve for d:

d = v . t

And we can also solve it for t:

\displaystyle t=\frac{d}{v}

Two cars move at different speeds and must travel a distance of d=110 km. The first car travels at v=90km/h. It takes a time of:

\displaystyle t_1=\frac{200}{90}=2.22\ h

Converting to minutes:

t_1=2.22*60= 133\ min

The second car travels at v=110km/h. It takes a time of:

\displaystyle t_2=\frac{200}{110}=1.82\ h

Converting to minutes:

t_2=1.82*60= 109\ min

The slower car takes 133 - 109 = 24 more minutes to reach its destination.

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In a "worst-case" design scenario, a 2000 kg elevator with broken cables is falling at 4.00 m/s when it first contacts a cushion
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Answer:

A. V =3.65m/s

B. a = 4m/s^2

Explanation:

Determine force of gravity (f) on the elevator.

f = mg

(m = 2000kg, g = 9.8m/s

2000kg × 9.8m/s^2= 19600N

Given,

Force of opposing friction clampforce of gravity = 17000N

the Net force on the elevator

= force of gravity - Force of opposing friction clamp

=19600 - 17000

= 2600 N

Lets determine the kinetic energy of the elevator at the point of contact with the spring

K.E = 1/2 m v^2

(m = 2000kg, v = 4.00m/s)

= (1/2) × 2000kg × (4m/s)^2

= 16000J

kinetic energy and energy gain will be absorbed by the spring across the next 2m

Therefore,

E = K.E + P.E

K.E = 16000J,

P.E of spring = net force absorbed × distance at compression

net force absorbed = 2600N and distance at compression = 2.0m)

P.E = 5200J

E = 16000J + 5200J

E = 21200 J

Note, spring constant wasn't given

Lets determine it's value

Using,

E = (1/2) × k × (x)^2

Where:

E = energy = 21200J, K = ?, X = 2m

21200J=(1/2) × k × (2m)^2

21200J × 2 =(4m)k

K = 42400J/4m

K = 10600 N/m

Therefore,

acceleration at 1m compression = ?

Using F = K × X

(F is force provided by the spring = 10600N/m, K = 10600 N/m and X = 1m)

= 10600N/m × 1m = 10600 N ( upward)

A. The speed of the elevator after it has moved downward 1.00 {\rm m} from the point where it first contacts a spring?

Using.

original Kinetic energy + net force on the elevator = final kinetic energy + spring energy

16000N + 2600N = (1/2)mv^2 + (1/2)k x^2

18600 = (1/2)(2000)(v^2) + (1/2)(10600N)(1^2)

18600 = 1000(v^2) + 5300

18600 - 5300 = 1000(v^2)

13300 = 1000(v^2)

V^2 = 13.300

V =3.65m/s

The acceleration of the elevator is 1.00 {\rm m} below point where it first contacts a spring

Spring constant = net force on the elevator + resultant force

(Spring constant = 10600N, net force on the elevator = 2600N, resultant force = ?)

10600N = 2600N + resultant force

resultant force = 10600N - 2600N

=8000N

Therefore

F = ma

a = f/m

(a = ?, f =8000N and m =2000kg)

= 8000 / 2000

a = 4m/s^2

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