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Lady_Fox [76]
3 years ago
15

A U-tube manometer is used to measure the pressure at the stagnation point of a model in a wind tunnel. One side of the manomete

r goes to an orifice at the stagnation point; the other side is open to the atmosphere (fig. below). If there is a difference of 3 cm in the mercury levels in the two tubes, what is the pressure difference in N/m2 .
Physics
1 answer:
slamgirl [31]3 years ago
3 0

Answer:

\Delta p=4000.4199\ Pa

Explanation:

Given:

  • difference in the column of mercury of u-tube manometer, \Delta h=3\ cm=0.03\ m

<u>We know that the pressure due to height if a liquid column is given as:</u>

p=\rho.g.h

where:

p = pressure

h = height of the liquid

\rho= density of the liquid

  • We have the density of mercury as, \rho=13593\ kg.m^{-3}

<u>Now the difference of pressure in the two tubes of the manometer:</u>

\Delta p=\rho.g.\Delta h

\Delta p=13593\times9.81\times0.03

\Delta p=4000.4199\ Pa

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