All categories

2 years ago

PLEASE HELP,, MARKING BRAINLIEST!!! Solve for the value of x.

Mathematics

1 answer:

iris [78.8K]2 years ago

3 0

Answer:

$\huge\boxed{\sf x = 37}$

Step-by-step explanation:

We know that,

The sum of interior angles of a triangle is 180 degrees.

So,

2x + 4 + 2x - 9 + x = 180

5x - 5 = 180

Add 5 to both sides

5x = 180 + 5

5x = 185

Divide both sides by 5

x = 185 / 5

x = 37

$\rule[225]{225}{2}$

Hope this helped!

You might be interested in

Help please asap!!<br> What are the units and degrees that u need to put in ?

FromTheMoon [43]

Answer:

This question is unanwserable without the "Spider Tool" If you would like to revise it i'd be happy to help

Step-by-step explanation:

But the units are degrees

8 0

3 years ago

A pancake recipe calls for 1 cup of flour. Derek has already used 1/4 cup of flour. How many more cups of flour does Derek need

Marat540 [252]

Answer:

Derek needs to add 3/4 cups of flour.

Step-by-step explanation:

If Derek has already used 1/4 cup of flour, he needs 3 more cups of flour to get to 1 full cup of flour.

4 0

2 years ago

Read 2 more answers

Two sides of a triangle measure 25cm and 35cm. which of the following could be the measure of the 3rd side

Bumek [7]

11 cm? Im not that good at this.. If im correct any of those would work

8 0

2 years ago

What is the security for the payment of a secured loan called

igomit [66]

The answer is C) collateral

8 0

3 years ago

The number of withdrawals a bank processes in a day follows a random variable X. The number of deposits in a day is represented

Serhud [2]

Answer:

Check the explanation

Step-by-step explanation:

Number of transactions in a day is sum of number of withdrawals and number of deposits. So,

Number of transactions in a day, Z = X + Y

Moment Generating function of Z is,

T+1

Expected number of transactions in a day = E[Z]

$= \frac{\mathrm{d} }{\mathrm{d} t}_{t=0}M_Z(t) = (r+1)\left ( \frac{p}{1-qe^t} \right )^{r} * \frac{-p}{(1-qe^t)^2} * (-qe^t) for t = 0$

$= (r+1)\left ( \frac{p}{1-qe^0} \right )^{r} * \frac{-p}{(1-qe^0)^2} * (-qe^0)$

$= (r+1)\left ( \frac{p}{1-q} \right )^{r} * \frac{-p}{(1-q)^2} * (-q)$

$= (r+1)\left ( \frac{p}{p} \right )^{r} * \frac{-p}{(p)^2} * (-q)$

$= \frac{(r+1)q}{p}$

4 0

2 years ago