Let x and y be your two consecutive whole numbers
x < sqrt(142) < y
x^2 < 142 < y
So, we are looking for x and y such that x^2 < 142 and y^2 > 142.
The closest squared number to 142 is 144 = 12^2.
Next is 11^2 = 121.
11 and 12 are consecutive.
11^2 = 121 < 142 < 144 = 12^2
Thus, 11 and 12 are your numbers
Answer: $5.00 is the range
Step-by-step explanation: Range is the largest number subtracted by the smallest, so $6 - $1 is $5.
Answer:
64
Step-by-step explanation:
if you do 64 + 18 you will get 82.
Answer:
The solution is (2,6)
Step-by-step explanation:
Let
x-----> the number of hours to change a fuel injection unit
y-----> the number of hours to change a transmission
we know that
5x+10y=70 -----> equation A
8x+8y=64 -----> equation B
Solve the system of equations by graphing
Remember that the solution of the system of equations is the intersection point both graphs
The solution is the point (2,6)
see the attached figure
Answer:
CV for statistics exam = 15%
CV for calculus exam = 19%
Since the CV for calculus exam is higher, it has a greater spread relative to the mean than the statistics exam.
Step-by-step explanation:
To find coefficient variation we use the formula:
CV = (SD/mean) * 100
CV for the statistics exam:
where; SD= 5
mean= 75
CV = ( 5/75) *100
= 0.15 or 15%
CV for calculus exam
SD = 11
Mean= 58
CV= (11 /58) * 100
= 0.19 or 19%
