Answer:
C. 2x^2-7x+7
Step-by-step explanation:
(3x^2-2x+2)-(x^2+5x-5) <em>Given</em>
From the given you will subtract like terms from both parenthesis.
3x^2-x^2=2x^2
-2x-5x=-7x
2-(-5)=7
Answer:
2 solutions
Step-by-step explanation:
I like to use a graphing calculator to find solutions for equations like these. The two solutions are ...
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To solve this algebraically, it is convenient to subtract 2x-7 from both sides of the equation:
3x(x -4) +5 -x -(2x -7) = 0
3x^2 -12x +5 -x -2x +7 = 0 . . . . . eliminate parentheses
3x^2 -15x +12 = 0 . . . . . . . . . . . . collect terms
3(x -1)(x -4) = 0 . . . . . . . . . . . . . . . factor
The values of x that make these factors zero are x=1 and x=4. These are the solutions to the equation. There are two solutions.
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<em>Alternate method</em>
Once you get to the quadratic form, you can find the number of solutions without actually finding the solutions. The discriminant is ...
d = b^2 -4ac . . . . where a, b, c are the coefficients in the form ax^2+bx+c
d = (-15)^2 -4(3)(12) = 225 -144 = 81
This positive value means the equation has 2 real solutions.
GFBH is the code
1 is -3,-2 which is G
2 is 3,4 which is F
3 is 2,0 which is B
4 is 1,-3 which is H
The answer is
-1 ≤ x < 3
We just learned this is in my algebra 2 AP class