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3 years ago

Sara halves it and gets an answer of 34.3. What was the original number?

Mathematics

1 answer:

Pavel [41]3 years ago

3 0

Answer: 68.6

because 34.3 times 2 is that or if u divide 68.6 by 2 u get 34.3

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You are deciding between two carnivals to attend. Carnuval A charges an entry fee of $15. Carnival B charges $5 for entry, plus

almond37 [142]

Answer:

Step-by-step explanation:

use these two equations

A: y = 15

B: y = 2r + 5

a) set the equations equal to eachother for your first answer

15 = 2r + 5

B) solve for r

15 = 2r + 5

10 = 2r

5 = r

after 5 rides the cost will be the same

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3 years ago

I need some urgent help, please.

frutty [35]

Answer: It's proportional

Step-by-step explanation: For every 0.5 Storage space (GB), you can fit 100 songs.

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3 years ago

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Which expression is a difference of cubes? 9w^33-y^12 18p^15-q^21 36a^22-b^16 64c^15- a^26

LiRa [457]

we know that

A polynomial in the form $a^{3}-b^{3}$ is called adifference of cubes. Both terms must be a perfect cubes

Let's verify each case to determine the solution to the problem

case A) $9w^{33} -y^{12}$

we know that

$9=3^{2}$ ------> the term is not a perfect cube

$w^{33}=(w^{11})^{3}$ ------> the term is a perfect cube

$y^{12}=(y^{4})^{3}$ ------> the term is a perfect cube

therefore

The expression $9w^{33} -y^{12}$ is not a difference of cubes because the term $9$ is not a perfect cube

case B) $18p^{15} -q^{21}$

we know that

$18=2*3^{2}$ ------> the term is not a perfect cube

$p^{15}=(p^{5})^{3}$ ------> the term is a perfect cube

$q^{21}=(q^{7})^{3}$ ------> the term is a perfect cube

therefore

The expression $18p^{15} -q^{21}$ is not a difference of cubes because the term $18$ is not a perfect cube

case C) $36a^{22} -b^{16}$

we know that

$36=2^{2}*3^{2}$ ------> the term is not a perfect cube

$a^{22}$ ------> the term is not a perfect cube

$b^{16}$ ------> the term is not a perfect cube

therefore

The expression $36a^{22} -b^{16}$ is not a difference of cubes because all terms are not perfect cubes

case D) $64c^{15} -a^{26}$

we know that

$64=2^{6}=(2^{2})^{3}$ ------> the term is a perfect cube

$c^{15}=(c^{5})^{3}$ ------> the term is a perfect cube

$a^{26}$ ------> the term is not a perfect cube

therefore

The expression $64c^{15} -a^{26}$ is not a difference of cubes because the term $a^{26}$ is not a perfect cube

I'm adding a new case so I can better explain the problem

case E) $64c^{15} -d^{27}$

we know that

$64=2^{6}=(2^{2})^{3}$ ------> the term is a perfect cube

$c^{15}=(c^{5})^{3}$ ------> the term is a perfect cube

$d^{27}=(d^{9})^{3}$ ------> the term is a perfect cube

Substitute

$64c^{15} -d^{27}=((2^{2})(c^{5}))^{3}-(d^{9})^{3}$

therefore

The expression $64c^{15} -d^{27}$ is a difference of cubes because all terms are perfect cubes

5 0

3 years ago

Read 2 more answers

Is 32>64/4 true or false

lisov135 [29]

Answer:

True

Step-by-step explanation:

You decide 4 into 64 and get your answer then you see if it is smaller than 32 in this case it is so the answer is true

3 0

3 years ago

If a man earns $420 interest in one year at 7%, what was the amount of money invested?

nordsb [41]

I(interest)=P(princple)R(rate)T(time)
I=420*.07*1=$29.4
A is correct.
Peace.

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3 years ago