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DENIUS [597]
3 years ago
13

If it snows tomorrow the probability is 0.8 that John will practice his trombone if it does not snow tomorrow there is only a 0.

5 chance that John will practice suppose the chance of snow tomorrow is 60% what is the probability that John will practice his trombone
Mathematics
1 answer:
Bas_tet [7]3 years ago
7 0

Answer:

0.68

Step-by-step explanation:

Given that :

P(trombone | snow) = 0.8 ;

P(trombone | no snow) = 0.5

P(snow) = 0.6

P(trombone) = P(trombone | snow) * p(snow) + P(trombone | no snow) * p(no snow)

P(no snow) = 1 - 0.6 = 0.4

Hence,

P(trombone) = P(trombone | snow) * p(snow) + P(trombone | no snow) * p(no snow)

P(trombone) = (0.8 * 0.6) + (0.5 * 0.4)

P(trombone) = 0.48 + 0.20

P(trombone) = 0.68

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2 years ago
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What is the domain for each function below? Choose the correct inequality symbol from the drop down menu and fill in the blank w
erik [133]

Answer:

x \le 3

x \ge 0

Step-by-step explanation:

The functions, missing from the question are:

f(x) = \sqrt{3 - x

f(x) = \sqrt{3 x

Required

Determine the domain

To get the domain, means we want to get the possible values of x.

(a)

f(x) = \sqrt{3 - x

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(b)

f(x) = \sqrt{3x

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4 0
2 years ago
A movie theater charges 8 dollars for adults and 4 dollars for seniors. On a particular day when 353 people paid an admission, t
sammy [17]

A movie theater charges 8 dollars for adults and 4 dollars for seniors. On a particular day when 353 people paid an admission, the total receipts were 1688 dollars. How many who paid were adults? . How many who paid were seniors?

<em><u>Answer:</u></em>

There were 69 adults and 284 seniors

<em><u>Solution:</u></em>

Let "a" be the number of adults

Let "s" be the number of seniors

Cost of 1 adult = $ 8

Cost of 1 senior = $ 4

<em><u>On a particular day when 353 people paid an admission</u></em>

Therefore,

number of adults + number of seniors = 353

a + s = 353

a = 353 - s ---------- eqn 1

<em><u>The total receipts were 1688 dollars</u></em>

Therefore, we frame a equation as:

number of adults x Cost of 1 adult + number of seniors x Cost of 1 senior = 1688

a \times 8 + s \times 4 = 1688

8a + 4s = 1688 ---------- eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

<em><u>Substitute eqn 1 in eqn 2</u></em>

8(353 - s) + 4s = 1688

2824 -8s + 4s = 1688

4s = 2824 - 1688

4s = 1136

<h3>s = 284</h3>

<em><u>Substitute s = 284 in eqn 1</u></em>

a = 353 - 284

<h3>a = 69</h3>

Thus there were 69 adults and 284 seniors in movie theater

7 0
2 years ago
S22 for 161+147+133+119+...
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Step-by-step explanation:

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