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yaroslaw [1]
3 years ago
7

todays Temperature is 3 degrees warmer than it yesterday. Write an expression for today's temperature

Mathematics
1 answer:
TiliK225 [7]3 years ago
4 0
T =temperature  d = day temp


t+3=d



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Charles has 24 marbles. He has 6 more marbles than blue marbles. Which equation represents this situation.
statuscvo [17]

Answer:

n + (n + 6) = 24.

Step-by-step explanation:

Let him have n  blue marbles, then he has n + 6 other narbles.

He has a total of 24 marbles, so:

n + (n + 6) = 24.

8 0
2 years ago
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Given h(x) = 4x + 3, find h(-1)<br>​
dsp73

Answer:

-1

Step-by-step explanation:

4x-1=-4

-4+3=-1

7 0
3 years ago
Find the GCF of the following monomials.<br> -50m⁴ n⁷ and 40m² n¹⁰
babunello [35]
Greetings!

We can factor this expression/ the GCF is:
-10m^2n^7

(-10m^2n^7)(5m^2-4n^3)

Hope this helps.
-Benjamin
8 0
3 years ago
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Use the zero product property to find the solutions to the equation x^2-15x-100=0
7nadin3 [17]

Answer:

x = 20 or x = -5

Step-by-step explanation:

To solve the quadratic equation we must factor the expression

Look for 2 numbers that when you multiply them, obtain the result -100 and when you add them, obtain the result -15.

You can verify that these numbers are -20 and 5

-20 +5 = -15\\\\-20 * 5 = -100

Then the polynomial factors are

(x-20) (x + 5) = 0

 The zero product property says that if two terms a * b = 0 then

a = 0 or b = 0

So

(x-20) = 0 or (x + 5) = 0

x = 20 or x = -5

6 0
3 years ago
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Assume that k and V0 are constant and are, respectively, 0.02, and 7. The parameter CA varies from an initial value CA0 = 100 to
julia-pushkina [17]

Answer:

V = 929.7

Step-by-step explanation:

Given the equation:

\frac{dCA}{dV} = \frac{-kCA}{V0}

The integral of the above equation is:

\int\limits {\frac{dCA}{dV} } = \int\limits{\frac{-kCA}{V0} }

Re-organizing the integrals:

\int\limits  {\frac{dCA}{CA} } = \int\limits {\frac{-kdV}{V0} }

Integrating:

ln(CA) - ln(CA0) = \frac{-kV}{V0}

Inputting the initial conditions of CA and the values of k and V0:

ln(7) - ln(100) = \frac{-0.02V}{7}

1.946 - 4.605 = -0.00286V

-2.659 = -0.00286V

=> V = \frac{2.659}{0.00286}

V = 929.720

Approximating to one decimal place,

V = 929.7

7 0
3 years ago
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