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Sophie [7]
2 years ago
12

A positive integer squared plus 3 times it’s consecutive integer is equal to 43

Mathematics
2 answers:
Jobisdone [24]2 years ago
5 0

Answer:

5

Step-by-step explanation:

let positive integer be x

x² + 3(x+1)=43

x²+3x+3-43=0

x² + 3x - 40 = 0

x² + 8x - 5x - 40 = 0

x(x+8) - 5(x+8)=0

(x-5)(x+8)=0

x-5=0 or x+8=0

x=5. or x=-8

but the question says positive integer,

therefore, x=5

Eduardwww [97]2 years ago
3 0

Answer:

the integer is 5

Step-by-step explanation:

x^2+3(x+1)=43

x^2+3x+3=43

x^2+3x+(9/4)=43-3+(9/4)

(x+(3/2))^2=42 1/4

x+(3/2)=sqrt(42 1/4)

x+(3/2)=6 1/2

x=(6 1/2)-(3/2)

x=5

check:

5^2+3(6)=43

25+18=43

43=43

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We can conclude that the value of x is (∠MNP + 66)/8 and angle m∠RNM = ∠RNQ - ∠MNP + 78.

<h3>What are angles?</h3>
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So,

  • ∠MNQ = ∠MNP + ∠PNQ
  • 8x + 12 = ∠MNP + 78
  • 8x + 12 - 78 = ∠MNP
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Now, substitute 'x = (∠MNP + 66)/8' in 8x + 12:

  • ∠MNQ = 8x + 12
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Hence, m∠RNM = ∠RNQ - ∠MNP + 78

Therefore, in the given question value of x is (∠MNP + 66)/8 and angle m∠RNM = ∠RNQ - ∠MNP + 78.

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