The value of x in the secants intersection is 1 units
The value of NM in the tangent and secant intersection is 51 units
<h3>How to find length when secant and tangent intersect?</h3>
The first question, two secant intersect outside the circle.
Therefore,
(6x + 8x)8x = (9 + 7)7
14x(8x) = 16(7)
112x² = 112
x² = 112 / 112
x = √1
x = 1
The second question, tangent and secant intersect,
Therefore,
(x + 3)² = (x - 3)(16 + x - 3)
(x + 3)² = (x - 3)(x + 13)
(x + 3)(x + 3) = (x - 3)(x + 13)
x² + 3x + 3x + 9 = x² + 13x - 3x - 39
x² + 9x + 9 = x² + 10x - 39
x² - x² + 9x - 10x = -39 - 9
-x = - 48
x = 48
NM = 48 + 3 = 51 units
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2.5y + 3x = 27
5x - 2.5y = 5
Align the variables to make solving this easier.
2.5y + 3x = 27
-2.5y + 5x = 5
You can see that the 2.5y and -2.5y cancel each other out. Then add the 3x and 5x, and 27 + 5.
3x = 27
5x = 5
8x = 32
Divide both sides by 8.
x = 4
Now input that x into one of the equations to get y.
2.5y + 3(4) = 27
2.5y + 12 = 27
2.5y = 15
y = 6
The answer to this system of equations is x = 4, y = 6. (4, 6)
Given :
Peter velocity , P = 30 mph .
Mitchell velocity , M = 40 mph .
Mitchell leaves 15 min later .
To Find :
If they drive along the same route how long will it take Mitchell to catch Peter.
Solution :
Distance covered by Peter in 15 min .

Let , time taken is x .
So , distance covered b them is equal :

Therefore , time taken by them is 45 minutes .
Hence , this is the required solution .
Answer:
3m+3p
Step-by-step explanation:
Sum of m and p is expressed as;
m + p (sum means addition)
If 3 is multiplied by the sum, this is expressed as;
3(m+p)
Expand
3m + 3p
Hence the required expression is 3m+3p