So the problem ask to find and convert the area into square meters. So to convert is you must do the cross multiplication process that could cancel out unit and made the answer into a square meter, so the answer would be 1. x10^-12m^2. I hope you are satisfied with my answer and feel free to ask for more
<span>Assuming the graph is y=-3(√2x)-4 and y=-3√(x-4) the transformation would be:
</span><span>The graph is compressed horizontally by a factor of 2
x=1/2x'
</span>y=-3(√2x)-4
y=-3(√x')-4 <span>
</span><span>moved left 4
x=x'-4
</span>y=-3(√x)-4
y=-3(√x'-4)-4
<span>
moved down 4
y=y'-4
</span>y=-3(√x-4)-4
y'-4=-3(√x'-4)-4
y'=-3(√x'-4)-4 +4
y'=-3(√x'-4)
Answer: C. <span>The graph is compressed horizontally by a factor of 2, moved left 4, and moved down 4.
</span>
Answer:
Area = 14.5
Step-by-step explanation:
Let's label the given coordinates A, B, C;
Thus;
A = (2, 3)
B = (-1, 0)
C = (2, -4)
From the coordinate geometry formula, the formula for area of a triangle with 3 vertices is;
Area = [Ax(By - Cy) + Bx(Cy - Ay) + Cx(Ay - By)]/2
Area = [2(0 - (-4)) + (-1)(-4 - 3) + 2(3 - (-4))]/2
Area = 29/2
Area = 14.5
Answer:
The answers is "
Option B".
Step-by-step explanation:
Where,
predicted value of lead content when traffic flow is 15.
Calculating thet-critical value
The lower predicted value 
When 
of CI use as the expected lead content:
