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Afina-wow [57]
3 years ago
12

Chemistry chemistry chemistry chemistry chemistry chemistry

Chemistry
2 answers:
fgiga [73]3 years ago
8 0

Explanation:

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klasskru [66]3 years ago
6 0

C H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R YC H E M I S T R Y

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Please help.
mojhsa [17]

Explanation: An element is represented in the form of _{A}^{Z}\textrm{X} where,

X = Symbol of the element

A = Atomic Mass of the element X

Z = Atomic Number of element X

Hence, For the element Justwondoricium,

Symbol = Jw

Atomic number = 120

Atomic Mass = 224

Now, Atomic number = Number of electrons = Number of Protons

Number of electrons = 120

Number of Protons = 120

and Atomic Mass = Number of neutrons + Number of protons

Number of neutrons can be calculated as we know atomic mass and number of neutrons, Putting the numbers we get

Number of neutrons = 224 - 120 = 104

The nearest noble gas to the element having atomic number 120 is Oganesson (Og), which has an atomic number of 118, so the next two electrons will be filled in the 8s orbital.

Electronic Configuration of Jw is [Og]8s^2

This electronic configuration lets us know about the location of the element in periodic table.

As the electron is entering the 8th shell, it belongs to the 8th period and as the last electron enters the s-orbital, it belongs to the S-block of the periodic table.

When the s-electrons are 1, it belongs to Group 1.

When the s-electrons are 2, it belongs to Group 2.

As this element has 2 s-electrons, it belongs to the Group 2.

8 0
3 years ago
Andrea and the other members of the tennis team are practicing hitting tennis balls. If two people hit identical balls at the sa
almond37 [142]

Answer:

D

Explanation:

The formula for calculating kinetic energy is 1/2mv^2, where m is the mass and v is the velocity or speed of the object. Since all of the balls have the same mass, the one with the highest speed or velocity will have the highest kinetic energy. Hope this helps!

8 0
3 years ago
Briefly describe how the pH of a colourless solution could be measured using a universal indicator​
Firdavs [7]

Answer:

Universal indicator can show us how strongly acidic or alkaline a solution is, not just that the solution is acidic or alkaline. This is measured using the pH scale , which runs from pH 0 to pH 14.

Explanation:

~Hope this helps

4 0
3 years ago
Construct a simulated 1H NMR spectrum for ethyl acetate by dragging and dropping the appropriate splitting patterns into the box
Ksju [112]

Answer:

The simulated 1H NMR spectrum for ethyl acetate is shown in the drawing attached.

Explanation:

To construct this NMR it is necessary to identify the essential components that can produce resonance peaks.

Two main groups can be identified, the acetyl group containing a sub-component (CH3) capable of producing a resonance peak, and the ethyl group containing two components (CH2 and CH3) each of which can produce on its own its own resonance peak.

6 0
3 years ago
QUESTION 3 A series of electrolytic deposition experiments is conducted. In each case, 10.0 Faradays is passed through the indiv
Neporo4naja [7]

The greatest molar amount of metal product is obtained from silver (1) nitrate.

Let us determine the mass of metal obtained in each case.

For La^3+;

La^3+ + 3e ----> La

1 mole of La is deposited by 3F

x moles of La is deposited by 10 F

x = 1 × 10/3

x = 3.33 moles

For Zn^2+;

1 mole Zn^2+ is deposited by 2F

x moles of Zn^2+ is deposited by 10 F

x = 5 F

For Ag^+

1 mole of Ag^+ is deposited by 1 F

x moles of Ag^+ is deposited by 10 F

x = 10 moles

For Ba^2+;

1 mole of Ba^2+ is deposited by 2 F

x moles of Ba^2+ is deposited by 10 F

x = 5 moles

Learn more: brainly.com/question/967776

6 0
2 years ago
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