PH of acidic buffer = pKa + log [CH₃COONa - HCl] / [CH₃COOH + HCl]
pKa of CH₃COOH = 4.74
Concentration of acetic acid in buffer = 2.0 M
Concentration of sodium acetate = 1.0 M
Concentration of HCl must add = x
pH = 4.74 + log (1-x) / (2+x) = 4.11
x = concentration of HCl must be added = 0.43 M
number of moles of HCl = M * V = 0.43 * 1 = 0.43 mol
mass of HCl must be added = 0.43 * 36.5 = 15.7 g
Answer:
The ability of the molecule to pack more tightly increases the melting point.
Explanation:
In hydrocarbons of same molecular formula, melting point is determined by:
- weak intermolecular forces
- Molecular symmetry
Higher the intermolecular forces and molecular symmetry, higher will be the melting point.
Intermolecular forces in hydrocarbons decreases with branching. Moreover, branching interfere the tight packing of the molecule in the crystal. Therefore, branched hydrocarbons tend to have lower melting point.
However, in highly branched hydrocarbons molecular symmetry increases which results in tight packing of the molecule in the crystal.
So, highly tight packed molecules tend to have high melting point.
As (CH3)2CHC(CH3)3 is highly branched and has high molecular symmetry, therefore, its melting point is highest among given.
So, among the given, option c is correct.
The answer is 6 because the number of chlorine is 2 so if you have 6 moles of chlorine the answer is 6