Answer:

Explanation:
Step 1. Determine the cell potential
<u> </u><u>E°/V</u><u> </u>
2MnO₄⁻ + 16H⁺ + 10e⁻ → 2Mn²⁺+ 8H₂O 1.507
<u>10Cl⁻ ⟶ 5Cl₂ + 10e⁻ </u> <u>-1.358 27
</u>
2MnO₄⁻ + 10Cl⁻ + 16H⁺⟶ 2Mn²⁺ + 5Cl₂ + 8H₂O 0.149
Step 2. Calculate K
The formula relating K and E is

E = 0.149 V
R = 8.314 J·K⁻¹mol⁻¹
T = 25 °C = 298.15 K
n = 10
F = 96 485 C/mol

The value of the equilibrium constant is 
Coefficients, you can’t change the subscripts but you can balance the equation by adding coefficients to both sides
A: BE has more ionization energy than LI
B: CA has more ionization energy than BA.
C: NA has more ionization energy than K
D: AR has more ionization energy than P
E: CI has a more ionization energy than SI
F: LI has more ionization energy than K
If any of these are wrong feel free to correct me in the comments.
Answer:
to collect liquid ethanol and leave ethene as a gas because ethanol has hydrogen bonds
Explanation:
The chemist would be lesser than the temperature of the mixture as to collect the liquid ethanol and then leave ethene as a gas since the ethanol is a bond that should be hydrogen. Also -OH that available in the ethanol would be responsible for the hydrogen bonds also it is the main and significant molecular forice
So as per the given situation the above represent the answer