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Zolol [24]
3 years ago
11

During the combustion of coal, the carbon in coal reacts with the oxygen in the atmosphere to form carbon dioxide. A, B, and C r

epresent the masses of compounds either used up or formed by the combustion of coal.
A = 12 grams, B = 44 grams, C = 32 grams

Which of the following statements supports the conclusion that combustion of coal follows the law of conservation?
A.The total mass of A and C, which are carbon dioxide and oxygen, is equal to the mass of B, which is carbon.
B.The total mass of A and C, which are carbon and oxygen, is equal to the mass of B, which is carbon dioxide.
C.The total mass of B and C, which are carbon and oxygen, is greater than the mass of A, which is carbon dioxide.
D.The total mass of A and B, which are carbon and oxygen, is greater than the mass of C, which is carbon dioxide.
Thank you to whoever tries to answer this and I will give brainliest if your answer is right!

Edit: Nevermind! I did more research and for whoever is also trying to find the answer to this question the correct one is B.!
Chemistry
2 answers:
VikaD [51]3 years ago
4 0
Answer: option <span>B.The total mass of A and C, which are carbon and oxygen, is equal to the mass of B, which is carbon dioxide.
</span>

Explanation:

1) The combustion of carbon is represented by the chemical equation:

C + O₂ → CO₂

2)  The law of conservation of mass states that the mass of the products is equal to the mass of the reactants.

3)  The reactants are C and O₂, while the product is CO₂.

4) The masses given are: A: 12 g, B: 44 g, and C: 32 g

Then, 12g + 32 g = 44 g, this is A + C = B.

Then, B represents the product, which is CO₂, whose molar mass is 44 g/mol.

Since, the molar mass of C is 12 g/mol, it is A; and since the molar mass of O₂ is 32, it is C.

Therefore, the answer is the option B.
<span />
SOVA2 [1]3 years ago
4 0

Answer: b i got it right

Explanation:

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2 years ago
If the cylindrical pistons are 25.000 cm in diameter at 20.0 ∘c, what should be the minimum diameter of the cylinders at that te
attashe74 [19]
Refer to the diagram shown below.

The piston supports the same load W at both temperatures.
The ideal gas law is
pV=nRT
where
p = pressure
V = volume
n = moles
T = temperature
R = gas constant

State 1:
T₁ = 20 C = 20+273 = 293 K
d₁ = 25 cm piston diameter

State 2:
T₂ = 150 C = 423 K
d₂ = piston diameter

Because V, n, and R remain the same between the two temperatures, therefore
\frac{p_{1}}{T_{1}} = \frac{p_{2}}{T_{2}}

If the supported load is W kg, then
p_{1} =  \frac{W \, N}{ \frac{\pi}{4} d_{1}^{2}} = \frac{4W \, N}{\pi (0.25 \, m)^{2}} =  20.3718W \, Pa
Similarly,
p_{2} =  \frac{4W}{\pi d_{2}^{2}} \, Pa

\frac{p_{1}}{p_{2}} =  \frac{20.3718 \pi d_{2}^{2}}{4} = 16 d_{2}^{2}

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Answer:

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Explanation:

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Average atomic mass = ?

Solution:

Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass)  / 100

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Average atomic mass  = 85.557 amu.

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Explanation:

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