Which statement correctly describes cellular respiration

What is the empirical formula for the following molecular formula: C10H5O2

Tju [1.3M]

The empirical formula is the same as the molecular formula : C₁₀H₅O₂

<h3>Further explanation</h3>

Given

Molecular formula : C₁₀H₅O₂

Required

The empirical formula

Solution

The empirical formula (EF) is the smallest comparison of atoms of compound forming elements.

The molecular formula (MF) is a formula that shows the number of atomic elements that make up a compound.

(empirical formula) n = molecular formula

(EF)n = C₁₀H₅O₂

If we divide by the number of moles of Oxygen (the smallest) which is 2 then the moles of Hydrogen will be a decimal number (not whole), which is 2.5, then the empirical formula is the same as the molecular formula

4 0

3 years ago

How does a negative ion differ from an uncharged atom of the same element?

Katena32 [7]

When an atom or molecule accepts or looses an electron or electrons it gets either negative charge (when electrons gained) or a positive charge (when looses electron). The negative ion is called Anion and positve ion is called the Cation. An Ion can be Atomic or Polyatomic.

Example:
Sodium when looses one electron forms a cation i.e. Na⁺

Chlorine when gains one electron forms an Anion i.e. Cl⁻

Result:
<span>A negative ion (Anion) differ from an uncharged atom of the same element in the number of electrons. An anion contains more electrons than its corresponding Neutral Element.</span>

4 0

4 years ago

Read 2 more answers

Describe the characteristics<br> of the different sections<br> (families) of the periodic<br> table

ANTONII [103]

Answer: The vertical columns on the periodic table are called groups or families because of their similar chemical behavior. All the members of a family of elements have the same number of valence electrons and similar chemical properties. The horizontal rows on the periodic table are called periods

6 0

3 years ago

A compound is found to contain 13.65 % carbon and 86.35 % fluorine by mass. To answer the question, enter the elements in the or

Nimfa-mama [501]

Answer: The molecular formula will be $CF_4$

Explanation:

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of C= 13.65 g

Mass of F = 86.35 g

Step 1 : convert given masses into moles.

Moles of C = $\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{13.65g}{12g/mole}=1.138moles$

Moles of F= $\frac{\text{ given mass of F}}{\text{ molar mass of F}}= \frac{86.35g}{19g/mole}=4.545moles$

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C = $\frac{1.138}{1.138}=1$

For F = $\frac{4.545}{1.138}=4$

The ratio of C : F= 1: 4

Hence the empirical formula is $CF_4$

The empirical weight of $CF$ = 1(12)+4(19)= 88g.

The molecular weight = 88.01 g/mole

Now we have to calculate the molecular formula.

$n=\frac{\text{Molecular weight }}{\text{Equivalent weight}}=\frac{88.01}{88}=$

The molecular formula will be= $1\times CF_4=CF_4$

5 0

4 years ago

Why is it not important to accurately measure the amount of 6 M HCl you place in your eudiometer tube

MissTica

It is not important to accurately measure the amount of HCl placed in the eudiometer tube since HCl will be added in excess to react with all the moles of Mg.

In gas stoichiometry, through the method of displacement of a liquid (generally water), the gaseous byproduct is collected inside a long, thin graded glass tube called a eudiometer.

If we consider a reaction between Magnesium and Hydrochloric acid to give a product known as magnesium chloride and hydrogen gas, we can have the chemical equation represented as:

$\mathbf{Mg_{(s)} + 2 HCl _{(aq)} \to MgCl_{2(aq)} + H_{2(g)}}$

From the above reaction, for each mole of Magnesium taking place in the reaction, 1 mole of hydrogen gas is also produced.

Thus, we can have a prediction that HCl can always be added in excess in order for us to react to all the moles of solid magnesium, hence, it is not important to measure the moles of HCl since it will be added in excess.

Learn more about gas stoichiometry here:

brainly.com/question/32160?referrer=searchResults

3 0

2 years ago