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2 years ago

29.3g CO2 and 20.8g H2O

Chemistry

1 answer:

docker41 [41]2 years ago

6 0

Answer:

the most best answer is 50.1 you never find such type of answer

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The energy of moving atoms is

balandron [24]

The answer is Thermal Energy :)

4 0

2 years ago

Read 2 more answers

HELP When 400 J of heat is added to 5.6 g of olive oil at 23*C, the temperature increases to 87*C. What is the specific heat of

babunello [35]

Q=mc*temperature change

400=5.6/1000*c*(87-23)

c=1160.07J/kg/k

4 0

3 years ago

Suppose a 10.0 mL sample of an unknown

mote1985 [20]

The concentration of HCl is equal to 2.54mol/L.

<h3>Mole calculation</h3>

To solve this question, one must use the molarity calculation, which corresponds to the following expression:

$M = \frac{mol}{v}$

Thus, to find the molarity of the sample, the following calculations must be performed:

$V_f = 10ml + 625ml = > 635ml$

$\frac{0.004mol}{xmol} =\frac{1000ml}{635ml}$

$x = 0.00254 mol$

So, 0.00254 moles were added per 10ml, so we can do:

$\frac{0.00254mol}{xmol}= \frac{10ml}{1000ml} \\x = 2.54mol/L$

So, the concentration of HCl is equal to 2.54mol/L.

Learn more about mole calculation in: brainly.com/question/2845237

6 0

2 years ago

A 65.0-gram sample of some unknown metal at 100.0° C is added to 100.8 grams of water at 22.0° C. The temperature of the water r

vampirchik [111]

We do a heat balance to solve this:
(m cp ΔT)water = -(m cp ΔT)metal
100.8 (4.18) (27 - 22) = -65 (cp)(27-100)
cp = 100.8 (4.18) (27 - 22) / (-65 (27-100))
cp = 0.44 J/ (°C × g)

The specific heat of the metal is 0.44 J/ (°C × g)

5 0

2 years ago

Part A

PilotLPTM [1.2K]

Answer:

4200ml

Explanation:

Converting 3.1kg to g

3.1*1000= 3100g

Since density = mass/volume, then

volume = mass/ density

Therefore volume = 3100/0.74

= 4189.2ml

converting it to two significant figures

= 4200ml

6 0

1 year ago