Explanation:
Percentage ethylene by weight = 57%
Percentage propylene by weight = 43%
Suppose in 100 grams of polymer:
Mass of ethylene = 57 g
Mass of propylene = 43 g
Moles of ethylene =
Moles of propylene =
1 mole = molecules/ atoms
Units of ethylene =
Units of propylene =
a) Fraction of ethylene units:
b ) Fraction of propylene units:
Explanation:
We will balance equation which describes the reaction between sulfuric acid and sodium bicarbonate: as follows.
Next we will calculate how many moles of are present in 85.00 mL of 1.500 M sulfuric acid.
As, Molarity =
1.500 M =
n = 0.1275 mol
Now set up and solve a stoichiometric conversion from moles of to grams of
. As, the molar mass of
is 84.01 g/mol.
= 21.42 g
So unfortunately, 15.00 grams of sodium bicarbonate will "not" be sufficient to completely neutralize the acid. You would need an additional 6.42 grams to complete the task.