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Mariana [72]
3 years ago
10

both sides in the war used military observers in hydrogen-filled balloons to watch the enemy's movements

Chemistry
1 answer:
lesya692 [45]3 years ago
7 0

Answer:

Yes.

Explanation:

Hydrogen-filled balloons were widely used by the militaries during World War I (1914–1918). The main purpose of these hydrogen-filled balloons to detect movements of enemy troops and to provide direction to the artillery fire. Balloons were the targets of opposing aircraft because they knew the purpose of these balloons so they hit it whenever seen by the enemies so we can say that both sides used hydrogen-filled balloons as military observer to watch the enemy's movements.

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While watching a popular space-based science fiction movie, space
Jobisdone [24]

Answer:

Sound waves required a medium.

Explanation:

In space, there is only vacuum hence no any medium for sound wave travel.

Since sound waves are mechanical waves, they require a material medium such as air, hence no sound transmission.

5 0
3 years ago
Complete the balanced equation for the reaction that occurs when formic acid (hcooh) dissolves in water. please include the stat
nignag [31]
Your balanced equation for this reaction is:

HCOOH (aq) + H2O (aq) → HCOO- (aq) + H3O+ (aq)

So from the reaction, we can see when formic acid dissolved in water so H3O+ ions will be formed.
and we can see that it is a balanced equation as:
we have H atoms = 4 on both sides of the reaction
and C atoms = 1 atom on both sides of the reaction
and O atoms = 3 atoms on both sides of the reaction
So it is our final balanced equation of the reaction.
8 0
3 years ago
In a chemical reaction, which are the most likely products of these reactants 4Fe+302
Cerrena [4.2K]

2Fe2O3, reason is when we add 4Fe + 3O2, we get the same answer, but in a different form.

8 0
3 years ago
Octane has a density of 0.703 g/ml. Calculate the mass of CO2(g) produced by burning one
STatiana [176]

The mass of CO₂ gas produced during the combustion of one gallon of octane is 8.21 kg.

The given parameters:

  • <em>Density of the octane, ρ = 0.703 g/ml</em>
  • <em>Volume of octane, v = 3.79 liters</em>

<em />

The mass of the octane burnt is calculated as follows;

m = \rho V\\\\m = 0.703 \ \frac{g}{ml} \times 3.79 \ L \ \frac{1000 \ ml}{L} \\\\m = 2,664.37 \ g

The combustion reaction of octane is given as;

2C_8H_{18} +  \ 25O_2 \ --> \ 16CO_2 \ + \ 18H_2O

From the reaction above:

228.46 g of octane -------------------> 704 g of  CO₂ gas

2,664.37 of octane --------------------> ? of CO₂ gas

= \frac{2,664.37 \times 704}{228.46} \\\\= 8,210.3 \ g\\\\= 8.21 \ kg

Thus, the mass of CO₂ gas produced during the combustion of one gallon of octane is 8.21 kg.

Learn more about combustion of organic compounds here: brainly.com/question/13272422

8 0
2 years ago
A plant uses energy from the sun to make food what kind of energy transformation is this
IRISSAK [1]

Answer:

photosynthesis

Explanation:

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5 0
3 years ago
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