Answer:
Hey mate
Explanation:
Yes these methods are only used in biology, chemistry, physics, geology and physcology.... They can't be used in maths or other subject, as it is said SCIENCE IS SCIENCE!
Hope it helps you,
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Answer:
cold
Explanation:
because being cold helps to refresh my body personally
Answer:
19.07 g mol^-1
Explanation:
The computation of the molecular mass of the unknown gas is shown below:
As we know that

where,
Diffusion rate of unknown gas = 155 mL/s
CO_2 diffusion rate = 102 mL/s
CO_2 molar mass = 44 g mol^-1
Unknown gas molercualr mass = M_unknown
Now placing these values to the above formula

After solving this, the molecular mass of the unknown gas is
= 19.07 g mol^-1
Multiple by 2 because it was give u right answer