Answer:
The mass of the beam is 0.074 kg
Explanation:
Given;
length of the uniform bar, = 1m = 100 cm
Set up this system with the given mass and support;
0-----------------33cm-----------------------------------100cm
↓ Δ ↓
0.15kg m
Where;
m is mass of the uniform bar
Apply the principle of moment to determine the value of "m"
sum of anticlockwise moment = sum of clockwise moment
0.15kg(33 - 0) = m(100 - 33)
0.15(33) = m(67)
![m = \frac{0.15kg(33 \ cm)}{67 \ cm}\\\\m = 0.074 \ kg](https://tex.z-dn.net/?f=m%20%3D%20%5Cfrac%7B0.15kg%2833%20%5C%20cm%29%7D%7B67%20%5C%20cm%7D%5C%5C%5C%5Cm%20%3D%200.074%20%5C%20kg)
Therefore, the mass of the beam is 0.074 kg