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nata0808 [166]
3 years ago
11

What do you need to know to describe the velocity of an object ?

Physics
1 answer:
Lelechka [254]3 years ago
3 0
<span>1. Rate of change of postion
2. Need to know the direction of the displacement or change of position

When you know these 2 things, you can describe an objects velocity
</span>
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A plane is flying east when it drops some supplies to a designated target below. The supplies land after falling for 10 seconds.
Ivanshal [37]

Part 1)

here we know that supply took 10 s to reach the ground

so here we will have

y = \frac{1}{2}gt^2

y = \frac{1}{2}\times 9.8 \times 10^2

y = \frac{1}{2}\times 9.8 \times 100

y = 490 m

Part 2)

Here all the supply covered horizontal distance of 650 m in 10 s interval of time

so here we can say

speed = \frac{distance}{time}

v = \frac{650}{10}

v = 65 m/s


4 0
3 years ago
F = 50 N<br> m = 72 kg<br> m/s2
lyudmila [28]

Answer:

Explanation:

F=ma

a=F/m

a=50/72=

a=0.694

3 0
3 years ago
A toaster using a Nichrome heating element operates on 120 V. When it is switched on at 28 ∘С, the heating element carries an in
sukhopar [10]

Answer:

The final temperature of the element = 262.67°C

The power dissipated in the heating element initially = 163.21 W

The power dissipated in the heating element when the current reaches 1.23 A = 147.60 W

Explanation:

Our given parameters include;

A Nichrome heating element operates on 120 V.

Voltage (V) = 120V

Initial Current (I₁) = 1.36 A

Initial Temperature (T₁) = 28°C

Final Current (I₂) = 1.23 A

Final Temperature (T₂) = unknown ????

Temperature dependencies of resistance is given by:

R_{T(2)}=R_1[1+\alpha (T_2-T_1)]            ----------------------    (1)

in which R₁ is the resistance at temperature T₁

R_{T(2) is the resistance at temperature T₂

Given that V= IR

R = \frac{V}{I}

Therefore, the resistance at temperature 28°C is;

R_{28}= \frac{120V}{1.36A}

= 88.24Ω

R_{T(2) = \frac{120V}{1.23A}

= 97.56Ω

From (1) above;

R_{T(2)}=R_1[1+\alpha (T_2-T_1)]      

97.56 = 88.24 [ 1 + 4.5×10⁻⁴(°C)⁻¹(T₂-28°C)]

\frac{97.56}{88.24}= 1+(4.5*10^{-4})(T-28^0C)

1.1056 - 1 = 4.5×10⁻⁴(°C)⁻¹(T₂-28°C)

0.1056 = 4.5×10⁻⁴(T₂-28°C)

\frac{0.1056}{4.5*10^{-4}}= T-28^0C

T - 28° C = 234.67

T = 234.67 + 28° C

T = 262.67 ° C

(b)

What is the power dissipated in the heating element initially and when the current reaches 1.23 A

The power dissipated in the heating element initially can be calculated as:

P = I²₁R₂₈

P = (1.36A)²(88.24Ω)

P = 163.209 W

P ≅ 163.21 W

The power dissipated in the heating element when the current reaches 1.23 A can be calculated as:

P= I^2_2R_{T^0C

P = (1.23)²(97.56Ω)

P = 147.598524

P ≅ 147.60 W

6 0
3 years ago
Your car's speedometer works in much the same way as its odometer, except that it converts the angular speed of the wheels to a
brilliants [131]

Answer:

Speed will be 30810 rpm      

Explanation:

We have given diameter of the tire d = 24 inch

So radius r=\frac{d}{2}=\frac{24}{2}=12imch

We have given linear velocity v = 35 mph

We know that linear velocity is given by v=\omega r

35=\omega \times 12

\omega =\frac{35}{12}\times \frac{63360}{60}=3080rad/min

As we know that 1 mile = 63360 inch and 1 hour = 60 min

3 0
3 years ago
Volleyball was invented in 1905.
Lady_Fox [76]

Answer:

REALLY??

Explanation:

8 0
2 years ago
Read 2 more answers
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