Question

Please Please PLEASE help me

Answer 1

Answer:

$x=\frac{-1}{4} +/-\frac{1}{4}\sqrt{17}$

Step-by-step explanation:

First, we need to get the equation into the polynomial form. Add 8 to both sides:

$-6x^{2} -2-3x=-8$

$-6x^{2} +6-3x=0$

Rearrange the equation so that it is in standard form:

$-6x^{2} -3x+6=0$

Remember the quadratic formula:

$\frac{-b+/-\sqrt{b^{2}-4ac} }{2a}$

$a$, $b$, and $c$ are the coefficients of the problem when it is in standard form. In this case, $a=-6$, $b=-3$, and $c=6$. Now, all we need to do is plug those into the quadratic formula.

$\frac{-(-3)+/-\sqrt{(-3)^{2}-4(-6)(6)} }{2(-6)}$

Simplify:

$\frac{3+/-\sqrt{153}}{-12}$

$x=\frac{-1}{4} +/-\frac{1}{4}\sqrt{17}$

Hope this helps!