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Brrunno [24]
3 years ago
9

Please Please PLEASE help me

Mathematics
1 answer:
MrMuchimi3 years ago
6 0

Answer:

x=\frac{-1}{4} +/-\frac{1}{4}\sqrt{17}

Step-by-step explanation:

First, we need to get the equation into the polynomial form. Add 8 to both sides:

-6x^{2} -2-3x=-8

-6x^{2} +6-3x=0

Rearrange the equation so that it is in standard form:

-6x^{2} -3x+6=0

Remember the quadratic formula:

\frac{-b+/-\sqrt{b^{2}-4ac} }{2a}

a, b, and c are the coefficients of the problem when it is in standard form. In this case, a=-6, b=-3, and c=6. Now, all we need to do is plug those into the quadratic formula.

\frac{-(-3)+/-\sqrt{(-3)^{2}-4(-6)(6)} }{2(-6)}

Simplify:

\frac{3+/-\sqrt{153}}{-12}

x=\frac{-1}{4} +/-\frac{1}{4}\sqrt{17}

Hope this helps!

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