"Prove that triangles are congruent by SSS property and hence angle EGF is equal to angle KML" is the step among the choices given that <span>can be used to prove that triangle EFG is also a right triangle. The correct option among all the options that are given in the question is the third option. I hope it helps you.</span>
Answer: a
Step-by-step explanation: a
If the vertex was at (-9,-5), then the range will only be ≤-5 or ≥-5.
The range could either be [-5,∞) or (-∞,-5].
Answer:
The solution set represented by the following graph is:
{x | x∈ R, x < -2}
Step-by-step explanation:
Clearly from the figure we could see that the solution set is to the left of ' -2' and excluding the point '-2' since there is a open circle at -2.
This means that -2 is not included in the set.
Also in interval; form the set of points that belong to the solution set are:
(-∞,-2)
in set-builder form it is written as:
{x | x∈ R, x < -2}
Using a t-distribution calculator, it is found that the critical value of the test statistic t is 
.
<h3>How to find the critical value of a t-test?</h3>
- The critical value is found using a calculator.
The inputs are:
- The amount of degrees of freedom, which is one less than the sample size.
In this problem, we have a<u> lower(left-tailed) test, with 10 - 1 = 9 df and a level of significance of 0.1</u>, hence the critical value is .
You can learn more about the t-distribution at brainly.com/question/26062194
