Answer:
P-value = 0.009997
Step-by-step explanation:
We are given the following in the question:
Sample size, n = 24
Nature of test: One-tailed test(Left tailed test)

We have to calculate the p-value.
Degree of freedom = n - 1 = 23
We calculate the p-value from the table corresponding to t score -2.50 and degree of freedom 23.
P-value = 0.009997
0.009997 is the probability of a value being to the left of a number that has a student-t statistic of –2.50.
You would have to use multiplication to do this problem.
The number setence would be : 11,220 x 10
The answer would be: 112,200
Answer: #2 CD=CA
Step-by-step explanation:
So sorry if wrong but i think it may be right.
GOOD LUCK!!
The third option. The translation would move it down, and the reflection would make the shape flip and move to the desired shape.