Help me plssss hurry!!!!Which expressions are equivalent to 6+(-4)

The voltage in an electrical circuit is multiplied by itself each time it is reduced. The voltage is 27/125 of a volt and it has

UkoKoshka [18]

Exponential form: F(x)= 3/125^x+1
Original voltage: 3/125 of a volt

5 0

3 years ago

Construct a 99% confidence interval for the population mean, mu. Assume the population has a normal distribution. A group of 1

Zarrin [17]

Answer:

99% confidence interval for the population mean is [19.891 , 24.909].

Step-by-step explanation:

We are given that a group of 19 randomly selected students has a mean age of 22.4 years with a standard deviation of 3.8 years.

Assuming the population has a normal distribution.

Firstly, the pivotal quantity for 99% confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean age of selected students = 22.4 years

s = sample standard deviation = 3.8 years

n = sample of students = 19

$\mu$ = population mean

<em>Here for constructing 99% confidence interval we have used t statistics because we don't know about population standard deviation.</em>

So, 99% confidence interval for the population mean, $\mu$ is ;

P(-2.878 < $t_1_8$ < 2.878) = 0.99 {As the critical value of t at 18 degree of

freedom are -2.878 & 2.878 with P = 0.5%}

P(-2.878 < $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ < 2.878) = 0.99

P( $-2.878 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X - \mu}$ < $2.878 \times {\frac{s}{\sqrt{n} } }$ ) = 0.99

P( $\bar X -2.878 \times {\frac{s}{\sqrt{n} }$ < $\mu$ < $\bar X +2.878 \times {\frac{s}{\sqrt{n} }$ ) = 0.99

<u>99% confidence interval for</u> $\mu$ = [ $\bar X -2.878 \times {\frac{s}{\sqrt{n} }$ , $\bar X +2.878 \times {\frac{s}{\sqrt{n} }$ ]

= [ $22.4 -2.878 \times {\frac{3.8}{\sqrt{19} }$ , $22.4 +2.878 \times {\frac{3.8}{\sqrt{19} }$ ]

= [19.891 , 24.909]

Therefore, 99% confidence interval for the population mean is [19.891 , 24.909].

6 0

3 years ago

A firm offers routine physical examinations as part of a health service program for its employees. The exams showed that 8% of t

Alexxandr [17]

Answer: A. 0.20

Step-by-step explanation:

Let A be the event of employees needed corrective shoes and B be the event that they needed major dental work .

We are given that : $P(A)=0.08\ ;\ P(B)=0.15\ ;\ P(A\cap B)=0.03$

We know that $P(A\cup B)=P(A)+P(B)-P(A\cap B)$

Then, $P(A\cup B)=0.08+0.15-0.03= 0.20$

Hence, the probability that an employee selected at random will need either corrective shoes or major dental work : $P(A\cup B)= 0.20$

hence, the correct option is (A).

6 0

3 years ago

What's bigger 7% or 0.7?

Dennis_Churaev [7]

7%

is the bigger number bc 0.7 is a decimal an it like ex.... 0.50th its like half of one whole percentage

do u see wat I mean

3 0

3 years ago

If I run 6 miles per hour. How fast do I run in km per minute?

Firdavs [7]

9.66 - you just multiple 6 by 1.61

7 0

3 years ago

Read 2 more answers

Help me plssss hurry!!!!Which expressions are equivalent to 6+(-4) - 5?