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SOVA2 [1]
3 years ago
6

Dakota received a mark of 68% on his math test.

Mathematics
2 answers:
topjm [15]3 years ago
7 0
Dakota answered 17 questions correctly.
amm18123 years ago
6 0
Dakota answers 17 questions right
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Solve the inequality 1/2c > -1​
Alexxandr [17]

Answer:

\frac{1}{2} c >  - 1

c >  - 1 \div  \frac{1}{2}

c >  - 1 \times 2

c >  - 2

6 0
3 years ago
3-3x6+2 and how is that reached, please!
Dvinal [7]
The order of mathematical operation is MDAS.
M - multiplication
D - division
A - addition
S - subtraction

3 - 3 x 6 + 2

Multiplication : 3 x 6 = 18
Division: none
Addition : + 3 + 2 = 5 (combine positive numbers)
Subtraction : 5 - 18 = -13

3 - 18 + 2 = -13
3 0
3 years ago
A regulation soccer goal net is 24 ft wide by 8 ft high. A soccer net for children is 6 ft wide. If the manufacturer wishes to k
oksian1 [2.3K]
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7 0
3 years ago
?<br> Which is the simplified form of n -6p3?
prohojiy [21]

<u>OPTION C</u>

if any doubt leave a comment

6 0
3 years ago
Read 2 more answers
40 points plz help if u can Which function has no Zeroes? Select all that apply.
Damm [24]
<h3>2 Answers: Choice C and choice D</h3>

y = csc(x) and y = sec(x)

==========================================================

Explanation:

The term "zeroes" in this case is the same as "roots" and "x intercepts". Any root is of the form (k, 0), where k is some real number. A root always occurs when y = 0.

Use GeoGebra, Desmos, or any graphing tool you prefer. If you graphed y = cos(x), you'll see that the curve crosses the x axis infinitely many times. Therefore, it has infinitely many roots. We can cross choice A off the list.

The same applies to...

  • y = cot(x)
  • y = sin(x)
  • y = tan(x)

So we can rule out choices B, E and F.

Only choice C and D have graphs that do not have any x intercepts at all.

------------

If you're curious why csc doesn't have any roots, consider the fact that

csc(x) = 1/sin(x)

and ask yourself "when is that fraction equal to zero?". The answer is "never" because the numerator is always 1, and the denominator cannot be zero. If the denominator were zero, then we'd have a division by zero error. So that's why csc(x) can't ever be zero. The same applies to sec(x) as well.

sec(x) = 1/cos(x)

7 0
3 years ago
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