<u>Answer:</u> The
of the acid is 6.09
<u>Explanation:</u>
For the given chemical reaction:

The expression of equilibrium constant [tex[(K_a)[/tex] for the above equation follows:
![K_a=\frac{[H^+][A^-]}{[HA]}](https://tex.z-dn.net/?f=K_a%3D%5Cfrac%7B%5BH%5E%2B%5D%5BA%5E-%5D%7D%7B%5BHA%5D%7D)
We are given:
![[HA]_{eq}=0.200M](https://tex.z-dn.net/?f=%5BHA%5D_%7Beq%7D%3D0.200M)
![[H^+]_{eq}=4.00\times 10^{-4}M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D_%7Beq%7D%3D4.00%5Ctimes%2010%5E%7B-4%7DM)
![[A^-]_{eq}=4.00\times 10^{-4}M](https://tex.z-dn.net/?f=%5BA%5E-%5D_%7Beq%7D%3D4.00%5Ctimes%2010%5E%7B-4%7DM)
Putting values in above expression, we get:

p-function is defined as the negative logarithm of any concentration.

So,

Hence, the
of the acid is 6.09
Answer:
a heterogeneous mixture
Explanation:
an example would be sand and water because it can be filtered which is a physical mean of separation.
Answer:
Technical program - cosmetologist
Answer:
n = 0.207 mole
Explanation:
We have,
P = 1 atm
V = 5 liter
R = 0.0821 L.atm/mol.K
T = 293 K
We need to find the value of n. The relation is as follows :
PV = nRT
Solving for n,

So, the value of n is 0.207 mol.