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Liula [17]
3 years ago
8

How long does it take to fill one train car full of nuclear power can keep a power plant running

Chemistry
1 answer:
olga_2 [115]3 years ago
5 0
Thats will last about 4 days
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What is significant about the elements within the same group of the periodic table?
loris [4]
<span>Well, for one, they have the same amount of electrons in the outmost shell: Group 1 has 1, Group 2 has 2 etc...They all share similar chemical properties, for example Group 6 (?) S and Se both are acidic oxides.</span>
8 0
3 years ago
If 15 grams of Carbon dioxide is produced in a chemical reaction, how many grams of Carbon must be consumed in the reaction if w
guajiro [1.7K]

Answer:

Quantity of Carbon is 4.09 gm

Explanation:

Equation of carbon reacting with oxygen to give carbon dioxide is given by

C + O_{2} ⇒ CO_{2}

One mole of carbon reacts with one mole of Oxygen in this reaction to give One mole of Carbon dioxide.

So, 12 gm of carbon reacts with 32 gm of Oxygen in this reaction to give 44 gm of carbon dioxide.

15 gm of CO_{2} was formed in this reaction

Oxygen used in this reaction = \frac{15}{44}×32 = 10.91 gm ,

Thus Oxygen is in sufficient quantity in the reaction.

Now,

Carbon that must be used = \frac{15}{44}×12  = 4.09 gm.

5 0
3 years ago
A chemist titrates 160.0mL of a 0.3403M aniline C6H5NH2 solution with 0.0501M HNO3 solution at 25°C . Calculate the pH at equiva
maxonik [38]

Answer : The pH of the solution is, 5.24

Explanation :

First we have to calculate the volume of HNO_3

Formula used :

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the initial molarity and volume of C_6H_5NH_2.

M_2\text{ and }V_2 are the final molarity and volume of HNO_3.

We are given:

M_1=0.3403M\\V_1=160.0mL\\M_2=0.0501M\\V_2=?

Putting values in above equation, we get:

0.3403M\times 160.0mL=0.0501M\times V_2\\\\V_2=1086.79mL

Now we have to calculate the total volume of solution.

Total volume of solution = Volume of C_6H_5NH_2 +  Volume of HNO_3

Total volume of solution = 160.0 mL + 1086.79 mL

Total volume of solution = 1246.79 mL

Now we have to calculate the Concentration of salt.

\text{Concentration of salt}=\frac{0.3403M}{1246.79mL}\times 160.0mL=0.0437M

Now we have to calculate the pH of the solution.

At equivalence point,

pOH=\frac{1}{2}[pK_w+pK_b+\log C]

pOH=\frac{1}{2}[14+4.87+\log (0.0437)]

pOH=8.76

pH+pOH=14\\\\pH=14-pOH\\\\pH=14-8.76\\\\pH=5.24

Thus, the pH of the solution is, 5.24

4 0
3 years ago
From his experiments ,j.j Thomson concludes what?
Vladimir [108]

Answer:

Thomson made the following conclusions: The cathode ray is composed of negatively-charged particles. The particles must exist as part of the atom, since the mass of each particle is only ∼ 20001​start fraction, 1, divided by, 2000, end fraction the mass of a hydrogen atom.

Explanation:

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3 years ago
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Answer:

Decay-the breakdown of dead plants..

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