According to this formula:
(P1V1) / T1 = (P2V2) / T2
convert T from C° to Kelvin:
T1 = 83 + 273 = 356 K
T2= 96 + 273 = 369 K
convert P from torr to atm:
1 torr = 0.00131578947 atm<span>
p1 = 0.839474 atm
P2 = 1.415789 atm
By substitution in the previous formula:
(0.839474 x 10.6 ) / (356) = ( 1.415789 x V2 ) / 369
So:
V2 = 6.5 L</span>
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Answer:
The correct answer is 2.75 grams of HCl.
Explanation:
The given balanced equation is:
CaCO₃ (s) + 2HCl (aq) ⇒ CaCl₂ (aq) + H₂O (l) + CO₂ (g)
Based on the given information, one mole of calcium carbonate is reacting with two moles of HCl. The molecular mass of HCl is 36.5 grams, thus, the mass of 2 moles of HCl will be, 36.5 × 2 = 73 grams
The molecular mass of CaCO₃ is 100 gram per mole, that is, the mass of 1 mole of CaCO₃ is 100 grams, therefore, the mass of HCl required for reacting with 3.75 grams of CaCO₃ will be,
= 3.75 × 2 × 36.5 / 100 = 2.74 grams of HCl.
