Answer:
https://www.google.com/url?sa=t&rct=j&q=&esrc=s&source=web&cd=1&ved=2ahUKEwjkwv-cqrjnAhVCheAKHWaFBBgQFjAAegQICBAB&url=https%3A%2F%2Fwww.acs.org%2Fcontent%2Fdam%2Facsorg%2Feducation%2Fresources%2Fk-8%2Finquiryinaction%2Fstudent-activity-sheets%2Fgrade-5%2Fchapter-3%2Flesson-3.3-forming-a-precipitate.pdf&usg=AOvVaw1fT7fpXG9PNWroM87puvgQ
Explanation:
that has the answers copy and paste it in your google
V = \sqrt{x} 3 * R * T / MW
V = RMS velocity
R = 8.3145 J/K*mole
T = Temperature K
MW = Molecular weigh in Kg
Answer:
NH3
Explanation:
2NH3(aq)+CO2(aq)→CH4N2O(aq)+H2O(l)
So for two moles of NH3 we need one mole of CO2. So let's count moles for each reagent.
n(NH3)=m(NH3)/M(NH3)=135700/17,03=7968.29 mol
n(CO2)=m(CO2)/M(CO2)=211400/44.01=4803.45 mol
From equation we have to divide n(NH3) by 2 because we need two equivalent per one CO2. That will be 3984.145. So the limiting agent is NH3 because it's not enough of it to react with all CO2
Answer is: osmotic pressure.
Osmotic pressure, alongside the vapor pressure depression, freezing point depression and the boiling point elevation are<span> the </span>colligative properties od solution.
<span>The direction of osmotic pressure is always from the side with the lower concentration (c = n/V) of solute to the side with the higher concentration.</span>
