<span>PV = nRT
(4000 Torr)(5 L) = n (62.4 Torr-L/mol-K)(296K)
n = 1.08 moles
28 g/mol, 1.08 moles = 30.3 grams
your answer is
C.30.3 g</span>
Ocean water freezes at a lower temperature than freshwater. ... Fresh water freezes at 32 degrees Fahrenheit but seawater freezes at about 28.4 degrees Fahrenheit , because of the salt in it.
Answer:
The Net reaction is
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Explanation:
From the Question we are told that the buffers are
and 
When NaOH is added the Net ionic reaction would be
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Answer:
I believe it is "Arsenenate"
Answer:
For these problems, we need to compare the theoretical yield that we'd get from performing stoichiometry to the actual yield stated in the problem. % yield is the actual yield/theoretical yield x 100%
Cu + 2 AgNO₠→ Cu(NOâ‚)â‚‚ + 2 Ag ==> each mole of copper yields two moles of silver
12.7-g Cu x ( 1 mol Cu /63.5-g Cu) x ( 2 mol Ag / 1 mol Cu) x (108-g Ag / 1 mol Ag) = 43.2-g Ag. This is the theoretical yield. Now, since we got 38.1-g Ag our % yield is:
38.1-g/43.2-g x 100% = 88.2%
Explanation:
