Answer:
The constant of proportionality is 2.50
Step-by-step explanation:
For a weight of 1 lb, the price is $2.50, so the price in dollars is related to the weight in pounds by the constant 2.50.
The constant of proportionality is 2.50 (dollars per pound).
Answer:
9.286
Step-by-step explanation:
I'm not guaranteeing this answer. If this is correctly written without any indication of how to deal with x, then here is as much as you can do.
850-53x m= 720-39x m Subtract 720 from both sides.
850 - 720 - 53x = 720 - 720 - 39xm Combine
- 53xm + 130 = - 39xm Add 53x
-53x+53xm + 130 = -39x + 53xm Combine
130 = 14xm Divide by 14
xm = 130/14
xm = 9.28
===============================
You can use the same steps above. I'm abbreviating the steps because they are the same.
I'm sure there is more to the problem, but I can't imagine what it is. If you have additional directions, put it under this answer. I will get it as a comment.
850-53m= 720-39m
850 - 720 - 53m = - 39m
130 - 53m = - 39m
130 = -39m + 53m
130 = 14m
130/14 = m
m =9.286
<span>Twelve diminished by six times a number</span>
<span> </span>
<span>12 - 6x </span>
What is the number line i'm sorry but i can help without a number line that this question is based off of.
It seems that the four graphs are the same and they do not have a negative change rate in the interval 0 to 2 in the x-axis.
A negative change rate means that when x increases the value of the function (y) decreases; this is, the function is decreasing in the interval being estudied, which is the same that going downward.
So, you must look for in your graphs where the equation is going downward.
For example, in the graph attached, that happens in any interval from negative infitity to 1.5.
The vertex will help you to identify it.
Given that the graph goes downward from negative infinity to the vertex, any interval that includes that range will have negative change.
You must look for a parabola that opens upward and whose vertex is in x = 2.
Read more on Brainly.com - brainly.com/question/3774202#readmore
