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EleoNora [17]
3 years ago
8

Which equation represents a line which is perpendicular to the line y=-\frac{1}{8}x+3

Mathematics
1 answer:
snow_tiger [21]3 years ago
6 0

Answer:

An equation with -8 as the slope.

Step-by-step explanation:

I can't see your choices but you need to look for an equation in which the slope is -8. A line with an opposite reciprocal slope is needed in order to be perpendicular to the line y = 1/8x + 3. The opposite reciprocal of 1/8 is -8.

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Solve for s.<br> S + 3s - 4 = 16<br> S =<br> Submit
const2013 [10]
The answer is 5 because 16+4=20 and 3s + s = 4s so you’re left with 4s = 20 and I know that 4 times 5 is 20.
ANSWER: S=5
3 0
3 years ago
HELP FAST‼️‼️
8_murik_8 [283]

Normal income: 25 $

Last week's income: 25 + 20: 45 $

% = Last week's/normal = 45/25 ×100 =180 %

7 0
2 years ago
There are 340 freshman at BHSS. This is one hundred less than two times the number of sophomores. Find the number of sophomores
natta225 [31]
To put it into an equation, it would be:

340 = 2x - 100

with x being the amount of sophomores at BHSS.

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340 + 100 = 2x

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The number of sophomores at BHSS is 220.




5 0
3 years ago
The sum of two confescutive integers is at least 46. What is the least possibly pair of integers?
dezoksy [38]
An integer is a whole number. Sum means to add and since they are consecutive, there is only a difference of 1 between them.

1) 21 + 23: not consecutive
2) 23+24= 47: has to be at least 46
3) 22+23= 45: has to be at least 46
4) 24+25= 49: has to be at least 46

So we have two possibilities: either #2 or #4. Find least possible pair of integers.

x= first integer
x+1= second integer

x + (x+1) >= 46
2x + 1 >=46
2x>=45
x>=22.5

Answer:
The first integer has to be greater than or equal to 22.5. Since integers are whole numbers, round up to the next whole number. The least possible integers are #2) 23 and 24.

Hope this helps! :)
3 0
3 years ago
What to the power of 4 equles 625
jeyben [28]

Answer:

5^4

Step-by-step explanation:

5x5x5x5=625

5 raised to the power of 4

4 0
3 years ago
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