Answer:
Explanation:
H3PO4(aq) + 3NaOH(aq) → Na3PO4(aq) + 3H2O(l)
mole of NaOH = 23.6 * 10 ⁻³L * 0.2M
= 0.00472mole
let x be the no of mole of H3PO4 required of 0.00472mole of NaOH
3 mole of NaOH required ------- 1 mole of H3PO4
0.00472mole of NaOH ----------x
cross multiply
3x = 0.0472
x = 0.00157mole
[H3PO4] = mole of H3PO4 / Vol. of H3PO4
= 0.00157mole / (10*10⁻³l)
= 0.157M
<h3>The concentration of unknown phosphoric acid is 0.157M</h3>
Answer:
70 180 000 kg
Explanation:
We can solve this problem by multiplying the amount of garbage each Canadian throws out each day (2.2 kg) by the number of Canadians:
- 2.2 kg/person * 31 900 000 persons = 70 180 000
Thus according to this problem, all Canadians throw out 70 180 000 kg of garbage each day.
Answer: Missing data related to question is attached below
If the KH,CH4 = 1.42 * 10^-3 mol/L atm
answer:
0.88 atm
Explanation:
P1 = 20 psi
aqueous concentration of methane in closed bottle = 20 ppm
20 ppm = 20 / 1000 ( gram / Kg ) = 0.020 gram/kg = 0.020 g/liter
molar mass of methane = 16 gram/mol
<em>next : convert mass conc to molar conc </em>
Cm = 0.020 / 16
Cm = 1.25 * 10^-3 mol/L
Given that KH,CH4 = 1.42 * 10-3 mol/L atm
Applying equilibrium relationship
Cm = ( KH,CH4 ) ( partial pressure of methane )
hence partial pressure of methane
= Cm / ( KH,CH4 ) = 1.25 * 10^3 / (1.42 * 10^-3 ) = 0.88 atm
Answer:
The equation for the rate of this reaction is R = [NO] + {O2}
Explanation:
The rate-determining step of a reaction is the slowest step of a chemical reaction which determines the rate (speed) at which the overall reaction would take place.
Reaction mechanism:
The slow and fast reactions both have NO3 which is cancelled out on both sides, in order to get the overall reaction.
The rate law for this reaction would be that for the rate determining step:
R = [NO] + {O2}
