Formaldehyde organic or inorganic

What is the hydrogen-ion concentration of the ph is 3.7

Komok [63]

Answer:

the answer 37

Explanation:

4 0

2 years ago

MgNH4PO4•6H2O loses H2O in a stepwise fashion as it is heated. Between 40 degrees celsius and 60 degrees celsius, the monohydrat

tino4ka555 [31]

Answer:

$\%\ Composition\ of\ phosphorus=20.00\ \%$

Explanation:

The molecular formula of the monohydrate formed = $MgNH_4PO_4.H_2O$

The molecular mass of the monohydrate formed = $Mass_{Mg}+Mass_{N}+6\times Mass_{H}+5\times Mass_O$

So, Mass = 24 + 14 + 6 × 1 + 5 × 16 = 155 g

Mass of phosphorus = 31 g

Thus,

$\%\ Composition\ of\ phosphorus =\frac{Mass_{phosphorus}}{Total\ mass}\times 100$

$\%\ Composition\ of\ phosphorus=\frac{31}{155}\times 100$

$\%\ Composition\ of\ phosphorus=20.00\ \%$

4 0

2 years ago

2. A 2.5 mol SAMPLE OF OXYGEN GAS (O2) INCREASES TO 3.2 mol

lana [24]

696.32 mmHg is the final pressure of the gas.

<h3>What is an ideal gas equation?</h3>

The ideal gas equation, pV = nRT, is an equation used to calculate either the pressure, volume, temperature or number of moles of a gas.

Given data:

$P_1$ = 720 mmHg

$P_2$ = ?

$n_1$ = 2.5 mol

$n_2$ = 3.2 mol

$V_1$ = 34 L

$V_2$ = 45 L

Formula

Combined gas law

$\frac{P_1 V_1}{n_1} = \frac{P_2 V_2}{n_2}$

$P_2$ = 696.32 mmHg

Hence, 696.32 mmHg is the final pressure of the gas.

Learn more about an ideal gas equation here:

brainly.com/question/19251972

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6 0

2 years ago

Magnesium ribbon reacts vigorously with hydrochloric acid. The test tube gets hot and bubbles are produced. When a metal reacts

oee [108]

The answer is C, hydrogen gas. This is because in single replacement reactions, the single element (here Magnesium) replaces whichever element in the compound it corresponds to. Because Mg loses electrons since it’s a metal, it will replace the element which also loses electrons, which is Hydrogen here. So when they switch places, MgCl2 and H2 are made— and H2 is the hydrogen gas.

6 0

2 years ago

Read 2 more answers

Select all of the following equations that represent an exothermic reaction.

masya89 [10]

Answer:

C(graphite) → C(diamond), ΔH = - 0.45 kcal

CH4 + 2O2 → CO2 + 2H2O + 212,800 cal

Explanation:

C(graphite) → C(diamond), ΔH = - 0.45 kcal

CH4 + 2O2 → CO2 + 2H2O + 212,800 cal

These reactions are exothermic reaction because heat is evolved.

The energy changes occur during the bonds formation and bonds breaking.

There are two types of reaction endothermic and exothermic reaction.

Endothermic reactions:

The type of reactions in which energy is absorbed are called endothermic reactions.

In this type of reaction energy needed to break the bond are higher than the energy released during bond formation.

For example:

C + H₂O → CO + H₂

ΔH = +131 kj/mol

it can be written as,

C + H₂O + 131 kj/mol → CO + H₂

Exothermic reaction:

The type of reactions in which energy is released are called exothermic reactions.

In this type of reaction energy needed to break the bonds are less than the energy released during the bond formation.

For example:

Chemical equation:

C + O₂ → CO₂

ΔH = -393 Kj/mol

it can be written as,

C + O₂ → CO₂ + 393 Kj/mol

6 0

2 years ago