Answer:
recordando también que ** 1mL = 1cm ^ 3 **
(como ** 1 dm ^ 3 = 1 L **)
Answer:
Final molarity of iodide ion C(I-) = 0.0143M
Explanation:
n = (m(FeI(2)))/(M(FeI(2))
Molar mass of FeI(3) = 55.85+(127 x 2) = 309.85g/mol
So n = 0.981/309.85 = 0.0031 mol
V(solution) = 150mL = 0.15L
C(AgNO3) = 35mM = 0.035M = 0.035m/L
n(AgNO3) = C(AgNO3) x V(solution)
= 0.035 x 0.15 = 0.00525 mol
(AgNO3) + FeI(3) = AgI(3) + FeNO3
So, n(FeI(3)) excess = 0.00525 - 0.0031 = 0.00215mol
C(I-) = C(FeI(3)) = [n(FeI(3)) excess]/ [V(solution)] = 0.00215/0.15 = 0.0143mol/L or 0.0143M
Answer:
Z=22.70
Explanation:
It is given that,
An element Z that has two naturally occurring isotopes with the following percent abundances as follows :
The isotope with a mass number 22 is 65.0% abundant; the isotope with a mass number 24 is 35.0% abundant.
The average atomic mass for element Z is given by :
So, the average atomic mass for element Z is 22.70.
Some bad people will tend to forge dollar bills and make fake bills, giving them to cashiers and asking for it to be split into a different amount of bills so they are given real cash and wont be caught or they will buy things, return them and be given back real money and get away with it. This is obviously a crime because it's fake.
Answer:
The answer to your question is letter D. 2.02 g
Explanation:
Data
moles of Ne = 0.100
atomic mass of Neon = 20.18 g
Process
1.- Use proportions to find the answer
20.18 g of Ne ------------------ 1 mol of Ne
x ------------------ 0.1 moles
x = (0.1 x 20.18)/1
x = 2.018
2.- Consider the significant figures
0.100 has three significant figures so the answer must be 2.02 g
