One way is that you can just factor it out: (x+2)(x+2)(x+2)
For the first pair, you get
![x^2+4x+4](https://tex.z-dn.net/?f=x%5E2%2B4x%2B4)
.
Then do
![(x^2+4x+4)](https://tex.z-dn.net/?f=%28x%5E2%2B4x%2B4%29)
*
![(x+2)](https://tex.z-dn.net/?f=%28x%2B2%29)
That will be
![x^3+6x^2+12x+8](https://tex.z-dn.net/?f=x%5E3%2B6x%5E2%2B12x%2B8)
So the answer is 6
Answer:
<em>The ladder touches the wall at 24 feet from the ground.</em>
Step-by-step explanation:
The wall of the building, the ground, and the ladder form a right triangle, whose longer side is the length of the ladder.
In any right triangle, we can apply Pythagora's theorem to find any missing side length.
The ladder is 26 feet in length, the distance from the bottom of the ladder and the building is 10 feet. Calling H to the distance above the ground where the ladder touches the wall, then:
![26^2=10^2+H^2](https://tex.z-dn.net/?f=26%5E2%3D10%5E2%2BH%5E2)
Calculating:
![676=100+H^2](https://tex.z-dn.net/?f=676%3D100%2BH%5E2)
Solving:
![H^2=676-100](https://tex.z-dn.net/?f=H%5E2%3D676-100)
![H^2=576](https://tex.z-dn.net/?f=H%5E2%3D576)
![H=\sqrt{576}](https://tex.z-dn.net/?f=H%3D%5Csqrt%7B576%7D)
H=24 feet
The ladder touches the wall at 24 feet from the ground.
Answer:
well if you subtract 29.5 minus 15.5 youn wil get 14
Step-by-step explanation:
Area of rhombus = 1/2 * diagonal * diagonal
72 = 1/2 * AC * BD
Diagonals bisect each other in a rhombus so if EC is 8 then AC is 16
72 = 1/2 * 16 * x - 1
72 = 8(x-1)
9 = x-1
X = 10
Check
72 = 1/2 * 16 * 10-1
72 = 1/2 * 16 * 9
72 = 8 * 9
72=72