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anastassius [24]
2 years ago
13

The length of a city block running north to south in New York City is about 5x10^-2 miles. The distance from New York City to Mu

mbai, India, is about 7.5x10^3 miles. The distance from new York City to Mumbai is about how many times the length of a New York City north-south block?
Show your work

I hate these idiotic math question the school makes me do.

Mathematics
1 answer:
ratelena [41]2 years ago
5 0

Answer:

<h2>15×10^4 </h2><h2>OR</h2><h2>150000</h2>

Step-by-step explanation:

Length of New York City Block = 5×10^-2

Distance from New York to Mumbai = 7.5×10^-3

The distance from new York City to Mumbai is about how many times the length of a New York City north-south block =

5 \times 10^-^2 \times x=7.5 \times 10^3

Solve the equation

5\times \:10^{-2}x=7.5\times \:10^3\\\\10^3=1000\\\\5\times \:10^{-2}x=1000\times \:7.5\\\\\mathrm{Multiply\:the\:numbers:}\:7.5\times \:1000=7500\\\\5\times \:10^{-2}x=7500\\\\Simplify\:5\times \:10^{-2} :\:\frac{1}{20} \\\\\frac{1}{20}x=7500\\\\\mathrm{Multiply\:both\:sides\:by\:}20\\\\20\times \frac{1}{20}x=7500\times \:20\\\\Simplify\\\\x=150000\\\\x = 15\times 10^4

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On Saturday, Lukas drove 4x – 5 miles. On Sunday, he drove 3x – 10 miles. What is the difference in miles driven?
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Answer:

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Step-by-step explanation:

(4x-5) - (3x-10) = ?

(4x-5) - 1 (3x-10) = ? DISTRIBUTE THE INVISIBLE -1 to (3x-10)

Turns into: 4x - 5 - 3x + 10

Which equals: x + 5

8 0
3 years ago
Each side length of a triangle is 4 cm. What type of triangle is it?
KIM [24]
Equilateral, because the sides are equal
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3 years ago
Write out the first four terms of the series to show how the series starts. Then find the sum of the series or show that it dive
Nostrana [21]

Answer:

The first four terms of the series are

(9+3),(\frac97+\frac35),(\frac9{7^2}+\frac3{5^2}),(\frac9{7^3}+\frac3{5^3})

\sum_{n=0}^\infty \frac9{7^n}+\frac{3}{5^n} = 14.25

Step-by-step explanation:

We know that

Sum of convergent series is also a convergent series.

We know that,

\sum_{k=0}^\infty a(r)^k

If the common ratio of a sequence |r| <1 then it is a convergent series.

The sum of the series is \sum_{k=0}^\infty a(r)^k=\frac{a}{1-r}

Given series,

\sum_{n=0}^\infty \frac9{7^n}+\frac{3}{5^n}

=(9+3)+(\frac97+\frac35)+(\frac9{7^2}+\frac3{5^2})+(\frac9{7^3}+\frac3{5^3})+.......

The first four terms of the series are

(9+3),(\frac97+\frac35),(\frac9{7^2}+\frac3{5^2}),(\frac9{7^3}+\frac3{5^3})

Let

S_n=\sum_{n=0}^\infty \frac{9}{7^n}    and     t_n=\sum_{n=0}^\infty \frac{3}{5^n}

Now for S_n,

S_n=9+\frac97+\frac{9}{7^2}+\frac9{7^3}+.......

    =\sum_{n=0}^\infty9(\frac 17)^n

It is a geometric series.

The common ratio of S_n is \frac17

The sum of the series

S_n=\sum_{n=0}^\infty \frac{9}{7^n}

    =\frac{9}{1-\frac17}

    =\frac{9}{\frac67}

    =\frac{9\times 7}{6}

    =10.5

Now for t_n

t_n= 3+\frac35+\frac{3}{5^2}+\frac3{5^3}+.......

    =\sum_{n=0}^\infty3(\frac 15)^n

It is a geometric series.

The common ratio of t_n is \frac15

The sum of the series

t_n=\sum_{n=0}^\infty \frac{3}{5^n}

    =\frac{3}{1-\frac15}

    =\frac{3}{\frac45}

    =\frac{3\times 5}{4}

    =3.75

The sum of the series is \sum_{n=0}^\infty \frac9{7^n}+\frac{3}{5^n}

                                        = S_n+t_n

                                       =10.5+3.75

                                       =14.25

4 0
3 years ago
What paces back and forth on the ocean floor
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the answer is A nervous wreck

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2 years ago
Rhonda wants to take out a 30-year, $280,000 loan with a 4.4% APR. She is considering purchasing 2 points, which will decrease h
Paha777 [63]

Given Information:

Loan amount = $280,000

Annual Percentage Rate = APR = 4.4% = 0.044

Number of years = 30

Required Information:

Monthly payment with points = ?

Monthly payment without points = ?

Answer:

Monthly payment with points = $1,361

Monthly payment without points = $1,402.13

Step-by-step explanation:

The monthly payment can be found using,

MP = P\times \frac{r\times (1+r)^{n}}{(1+r)^{n} - 1}

P is the loan amount.

Where interest rate r is given by

r = \frac{APR}{12}

Total number of payments n are given by

n = 30\times12 = 360

Monthly payment with points:

Rhonda is considering purchasing 2 points and each decreases APR by 0.125%

So the APR becomes

APR = 4.4\% - 0.125(2)\\\\APR = 4.4\% - 0.25\%\\\\APR = 4.15\%

and the corresponding interest rate r is

r = \frac{APR}{12}\\\\r = \frac{4.15\%}{12}\\\\r = 0.3458\% \\\\r = 0.003458

Finally, the monthly payment is

MP =280,000\times \frac{0.003458\times (1+0.003458)^{360}}{(1+0.003458)^{360} - 1}\\\\MP =280,000\times 0.0048608 \\\\MP = \$ 1,361

Monthly payment without points:

Interest rate r is,

r = \frac{APR}{12} \\\\r = \frac{4.4}{12} \\\\r = 0.3667\% \\\\r = 0.003667

Monthly payment is,

MP =280,000\times \frac{0.003667\times (1+0.003667)^{360}}{(1+0.003667)^{360} - 1}\\\\MP =280,000\times 0.0050076 \\\\MP = \$ 1,402.13

So monthly payment with points is $1,361 and monthly payment without points is $1,402.13

6 0
3 years ago
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