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Jet001 [13]
2 years ago
11

Need help asap!! Tyyy

Mathematics
1 answer:
bagirrra123 [75]2 years ago
6 0

Answer:

42y + 12

Step-by-step explanation:

Simplify by applying the distributed property:

  1. 6 × 7y = 42y
  2. 6 × 2 = 12
  3. Put them together: 42y + 12

I hope this helps!

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A charity is selling raffle tickets at $5 apiece. Out of the 100 tickets sold, ten third-place winners will be drawn, each winni
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The answer is <span>No, because one ticket’s expected value is worth $0.50 more than the face value. </span>
3 0
3 years ago
Read 2 more answers
Evaluate cos(37°15').<br><br> 0.7944<br> 0.7960<br> 0.7971
Anvisha [2.4K]

cos(37°15') = cos(37.25°) ≈ 0.7960

15' means 15/60 of a degree, or 0.25 degrees.

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Note: the calculator mode is set to <em>Degrees</em>.

5 0
3 years ago
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3(x + 1) = -2(x - 1) - 4
Svetllana [295]

Answer:

<h2><em><u>x = -1</u></em></h2>

Step-by-step explanation:

<em><u>1. Distribute</u></em>

3x + 3 = -2x + 2 - 4

<em><u>2. Simplify</u></em>

-2x + 2 - 4

2-4 = -2

-2x - 2

<em><u>3. Solve</u></em>

3x + 3 = -2x - 2

+2x       +2x

<em><u>4. Cont. Solving</u></em>

5x + 3 = -2

     -3     -3

5x = -5

<em><u>5. Divide by 5</u></em>

5x = -5

/5      /5

<h2><em><u>x = -1</u></em></h2><h2><em><u /></em></h2>

Hope this helped,

Kavitha Banarjee

8 0
3 years ago
A couple wants to have three children. Assume that the probabilities of a newborn being male or being female are the same and th
liberstina [14]

Answer:

Let the G represent the Girl child

and, B represents the Boy child.

Then Sample Space = {BGG, GBG, GGB, BBG, BGB, GBB, BBB, GGG}

Thus, There are 8 sample space.

Then, Probability that couple have 1 boy = {BGG, GBG, GGB}

=  3 ÷ 8 = 0.375

Probability that couple have 2 boys = { BBG, BGB, GBB}

= 3 ÷ 8 = 0.375

Probability that couple have 3 boys = {GGG}

= 1 ÷ 8 = 0.125

7 0
3 years ago
The "P" in 20p9 represents a:
Scorpion4ik [409]

Answer:

option (A) —Permutation.

Step-by-step explanation:

this is because permutation comes in this form and looks like that and I have learnt permutation in the past.

so yeah;

examples of permutations:

²⁰p9 ( 20 upper case, 9 lower case and p in-between)

we can solve it by

Formula: n!/(n-r)!

soooo

20!/(20-9)!

= 20!/(11)!

=20x19x18x17x16x15x14x13x12x11!/11!

we cancel out the 11!s (for easier solving)

and multiply or cancel out the remaining ( if you can't cancel out yet just multiply)

we get,

6.09493248 x 10¹⁰

~ 6 x 10¹⁰

there you go.( I know I did a little bit too much)

Hope this helps

Good luck.

7 0
2 years ago
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