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natta225 [31]
3 years ago
5

Brainlist +50points plzz fast asp​

Computers and Technology
1 answer:
Lelechka [254]3 years ago
4 0

Answer:

20. Quick access toolbar.

21. Toggle buttons.

22. Secondary memory.

23. Recycle bin.

24. System tray.

25. Basic and high contrast.

Part III.

1. Existing.

2. Cut.

3. Outline.

4. Title.

5. emails.

6. Web-browser.

7. Slides.

8. Ubdo

9. Ctrl + I.

10. Start button.

11. Screen.

12. Binary.

13. Formatting.

14. System.

15. Volatile memory.

16. Hard.

17. Engine.

18. Zone.

19. Picture.

20. Modify.

Explanation:

20. By default Undo and Redo commands are located on Quick access toolbar.

21. The B, I and U buttons are called toggle buttons.

22. The memory which is called the auxiliary memory is secondary memory.

23. When you delete a file or folder it goes to the Recycle bin.

24. System tray is present on the right side of the taskbar.

25. Basic and high contrast is one set of themes.

<u>Part III.</u>

1. Renaming a file or folder means to give a new name to an existing file or folder.

2. You can shift a file or folder using the cut and paste.

3. Outline tab displays the text in the presentation

4. The title bar is on the top of the MS PowerPoint screen.

5. The mail button of Internet explorer allows you to send receive and view emails.

6. Web-browser allows you to view web pages.

7. A presentation is a collection of slides.

8. Undo cancels the last executed command.

9. The keyboard shortcut for italics is Ctrl + I.

10. We can go to any software that is loaded on our computer through the start button.

11. You can also design your own screen saver.

12. Computer understands only binary language.

13. Formatting means changing the appearance of a document.

14. Every computer has a system clock.

15. RAM is also called volatile memory.

16. The information stored on the hard disk remains there even if the computer is switched off.

17. Search engine searches for keywords or categories you specify and then shows you a list of the words related to the key word.

18. Countries and places in the same time zone read the same time.

19. Use picture position option for specifying the positioning of the wallpaper.

20. You can modify the copied independently file without affecting original file.

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You should process the tokens by taking the first letter of every fifth word,starting with the first word in the file. Convert t
zhenek [66]

Answer:

See explaination

Explanation:

import java.io.File;

import java.io.IOException;

import java.util.Scanner;

import java.util.StringTokenizer;

public class SecretMessage {

public static void main(String[] args)throws IOException

{

File file = new File("secret.txt");

StringBuilder stringBuilder = new StringBuilder();

String str; char ch; int numberOfTokens = 1; // Changed the count to 1 as we already consider first workd as 1

if(file.exists())

{

Scanner inFile = new Scanner(file);

StringTokenizer line = new StringTokenizer(inFile.nextLine()); // Since the secret.txt file has only one line we dont need to loop through the file

ch = line.nextToken().toUpperCase().charAt(0); // Storing the first character of first word to string builder as mentioned in problem

stringBuilder = stringBuilder.append(ch);

while(line.hasMoreTokens()) { // Looping through each token of line read using Scanner.

str= line.nextToken();

numberOfTokens += 1; // Incrementing the numberOfTokens by one.

if(numberOfTokens == 5) { // Checking if it is the fifth word

ch = str.toUpperCase().charAt(0);

stringBuilder = stringBuilder.append(ch);

numberOfTokens =0;

}

}

System.out.println("----Secret Message----"+ stringBuilder);

}

}

}

5 0
3 years ago
Memory containing hardwired instructions that the computer uses when it boots up, before the system loads. In PCs the instructio
VladimirAG [237]

Answer:

<h2>Rom</h2>

Explanation:

ROM is memory containing hardwired instructions that the computer uses when it boots up, before the system software loads

4 0
3 years ago
Read 2 more answers
0111101101010110101110110001001011101001011101101010101010110101
rodikova [14]

Answer:

binary digits in computer system it belongs

4 0
3 years ago
Write a Java program to encrypt and decrypt a phrase using two similar approaches, each insecure by modern standards. The first
xeze [42]

Answer:

See explaination

Explanation:

//CryptoManager.java

public class CryptoManager {

static int LOWER_BOUND=32;

static int UPPER_BOUND=95;

/*This method determines if a string is within the allowable bounds of ASCII

codes according to the LOWER_BOUND and UPPER_BOUND characters. The parameter

plainText is the string to be encrypted. The method returns true if all

characters are within the allowable bounds, false if any character is outside.*/

public static boolean stringInBounds (String plainText)

{

boolean flag=true;

//determines if a string is within the allowable bounds of ASCII

//codes according to the LOWER_BOUND and UPPER_BOUND characters.

for(int i=0;i<plainText.length();i++)

{

if(!((int)plainText.charAt(i)>=LOWER_BOUND && (int)plainText.charAt(i)<=UPPER_BOUND))

{ //false if any character is outside the bounds

flag=false;

break;

}

}

//returns true if all characters are within the allowable bounds

return flag;

}

/*This method encrypts a string according to the Caesar Cipher. The integer key

specifies an offset and each character in plainText is replaced by the character

the specified distance away from it. The parameter plainText is an uppercase

string to be encrypted. The parameter key is an integer that specifies the

offset of each character. The method returns the encrypted string.*/

public static String encryptCaesar(String plainText, int key)

{

//Wrap around the key, if it is greater than the UPPER_BOUND

key=Wrap_around(key);

//encrypted text

String res="";

//encryption

for(int i=0;i<plainText.length();i++)

{

res+=Character.toString((char) ((int)plainText.charAt(i)+key));

}

//return result

return res;

}

/* This method decrypts a string according to the Caesar Cipher. The integer

key specifies an offset and each character in encryptedText is replaced by

the character "offset" characters before it. This is the inverse of the

encryptCaesar method. The parameter encryptedText is the encrypted string

to be decrypted, and key is the integer used to encrypt the original text.

The method returns the original plain text string.*/

public static String decryptCaesar(String encryptedText, int key){

//Wrap around the key, if it is greater than the UPPER_BOUND

key=Wrap_around(key);

//decrypted text

String org="";

//encryption

for(int i=0;i<encryptedText.length();i++)

{

org+=Character.toString((char) ((int)encryptedText.charAt(i)-key));

}

//return result

return org;

}

public static int Wrap_around(int key)

{

while(key>UPPER_BOUND)

{

key-=(UPPER_BOUND-LOWER_BOUND);

}

return key;

}

/* This method encrypts a string according to the Bellaso Cipher. Each character

in plainText is offset according to the ASCII value of the corresponding

character in bellasoStr, which is repeated to correspond to the length of

plaintext. The method returns the encrypted string.*/

public static String encryptBellaso(String plainText, String bellasoStr)

{

//encrypted text

String res="";

//Adjust length of bellasoStr to plainText

while(bellasoStr.length()<plainText.length())

{

bellasoStr+=bellasoStr.substring(0,(plainText.length()-bellasoStr.length()));

}

//encryption

for(int i=0;i<plainText.length();i++)

{

char c=(char)Wrap_around((int)plainText.charAt(i)+(int)bellasoStr.charAt(i) );

res+=Character.toString(c);

}

//return result

return res;

}

/*

This method decrypts a string according to the Bellaso Cipher. Each character

in encryptedText is replaced by the character corresponding to the character in

bellasoStr, which is repeated to correspond to the length of plainText. This is

the inverse of the encryptBellaso method. The parameter encryptedText is the

encrypted string to be decrypted, and bellasoStr is the string used to encrypt

the original text. The method returns the original plain text string.*/

public static String decryptBellaso(String encryptedText, String bellasoStr)

{

//decrypted text

String res="";

//Adjust length of bellasoStr to plainText

while(bellasoStr.length()<encryptedText.length())

{

bellasoStr+=bellasoStr.substring(0,(encryptedText.length()-bellasoStr.length()));

}

//decryption

for(int i=0;i<encryptedText.length();i++)

{

char c=(char)Wrap_around((int)encryptedText.charAt(i)-(int)bellasoStr.charAt(i) );

res+=Character.toString(c);

}

//return result

return res;

}

}

6 0
3 years ago
Crossing out answers that could not possibly be correct is called ‘eliminating answers.’ Please select the best answer from the
BaLLatris [955]

The correct answer is True.

Explanation

When we must solve a multiple-choice test or exam, in most cases, we are asked to select only one choice from four or more options. This means we need to know which is the correct answer from the options given to obtain a good grade. Due to this, we must be very precise when responding and paying attention to details because many times the answers are very similar, but only one contains all the elements that answer the question.

One of the most used methods to do this is "eliminating answers" this means we discard answers that we are sure are not possible answers by crossing out these and leaving only the correct answer or a few possible correct answers, in this case, we will need to analyze the remaining answers to select the most appropriate. So, the correct answer is True.

6 0
4 years ago
Read 2 more answers
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