Answer:
The mole fraction of NaOH in an aqueous solution that contain 22.9% NaOH by mass=0.882
Explanation:
We are given that
Aqueous solution that contains 22.9% NaOH by mass means
22.9 g NaOH in 100 g solution.
Mass of NaOH(WB)=22.9 g
Mass of water =100-22.9=77.1
Na=23
O=16
H=1.01
Molar mass of NaOH(MB)=23+16+1.01=40.01
Number of moles =
Using the formula
Number of moles of NaOH
Molar mass of water=16+2(1.01)=18.02g
Number of moles of water
Now, mole fraction of NaOH
=
=0.882
Hence, the mole fraction of NaOH in an aqueous solution that contain 22.9% NaOH by mass=0.882
Answer:
The balanced equation is: H2 (g) +Cl2 (g) →2HCl (g)
Explanation:
Balancing chemical equation refers to balancing the stoichiometric coefficients on the reactants and products side. This must be done as the chemical equation obeys the law of conservation of mass and momentum.
The representation of a chemical reaction in the form of substances is known as a chemical equation. The equation in which the number of atoms of all the molecules is equal on both sides of the equation is known as a balanced chemical equation. The Law of conservation of mass governs the balancing of a chemical equation.
Given chemical equation
The balanced chemical equation for the hydrogen + chlorine -> Hydrogen Chloride.
H2 + Cl2 → 2HCl
The equation is balanced as on the reactants side there are two hydrogens present and the same on the products side. For chlorine as well the same thing goes two chlorine atoms on the reactants side and two on the products side.
Standard temperature is 273 K
Standard pressure is 1 atm
We use the ideal gas equation to find out density of nitrogen gas in g/L
Ideal gas equation:
Molar mass of
Pressure = 1 atm
Temperature = 273 K
= 1.25 g/L
Therefore, density of nitrogen gas at STP is 1.25 g/L
Answer: 80 ml
Explanation:
V= vol ml, C = concentration %
V1 = 20ml, C1 = 20%
V2 = ? , C2 = 5%
V1C1 = V2C2
V2 = (V1C1)/C2
V2 = (20ml x 20%) / 5% = 80 ml