The volume occupied by 0.118mol of He gas at a pressure of 1.05 atm and temperature of 322k is calculated by use of ideal gas equation
that is PV = nRT
P(Pressure)1.05 atm
v(volume)=?
n (number of moles)=0.118 mol
T(temperature)= 322K
from equation above volume(v)= nRT/p
volume(v) = (0.118 mol x 0.0821 L.atm/k.mol x322k) / 1.05 atm = 2.97 L
<u>Answer:</u> The edge length of the unit cell is 0.461 nm
<u>Explanation:</u>
We are given:
Atomic radius of iridium = 0.163 nm
To calculate the edge length, we use the relation between the radius and edge length for FCC lattice:
Putting values in above equation, we get:
Hence, the edge length of the unit cell is 0.461 nm
"The forces of attraction and the volume of the molecules" (as opposed to the volume of the container the gas is in).
Answer:
They are all organic compounds
Explanation:
Methanol, ethanoic acid and glucose are all organic compound that can be found in living organisms.
Glucose is a product of photosynthesis in plants. It is also produced from digestion of food in animals.
Ethanoic acid is a product of cellular respiration that occurs where there is insufficient oxygen.
Methanol is a waste often found in urine.
These compounds can all be traced to living sources. They are called organic compounds.
Here we have to get the possible isomers of hexene C₆H₁₂ which have no branching and cis, trans form.
The alkene isomers those are possible for C₆H₁₂ without any branch and e/z isomers is 1-hexene.
The isomers are possible without any branch for C₆H₁₂ may be 1-hexene, 2-hexene and 3-hexene.
But without e/z isomers mean the structure should not have any cis, trans form.
Now the 2-hexene and 3-hexene both have cis, trans isomerism. Only 1-hexene will not have any branch chain and e/z isomers.
Thus the name of the alkene isomer having C₆H₁₂ formula is determined.