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3 years ago

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Anyone think they can help me with this one?

1 answer:

BARSIC [14]3 years ago

4 0

To name this Alkyne, simply count from the direction that will give the lowest starting number to appear at the beginning of the carbon triple bond.

If you were to count from the top of the chain, the position of the carbon next to the triple bond would be 4. Yet if you count from the bottom chain going left to right and above the chain, the position of the carbon next to the triple bond would be 3.

Then identify the groups that are connected off the parent chain, here we have a methyl group on carbon 2.

Thus the name would be 2 - methyl - 3 - heptyne. I believe.

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Answer : The value of $pK_a$ of the weak acid is, 4.72

Explanation :

First we have to calculate the moles of KOH.

$\text{Moles of }KOH=\text{Concentration of }KOH\times \text{Volume of solution}$

$\text{Moles of }KOH=3.00M\times 10.0mL=30mmol=0.03mol$

Now we have to calculate the value of $pK_a$ of the weak acid.

The equilibrium chemical reaction is:

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Initial moles 0.25 0.03 0

At eqm. (0.25-0.03) 0.03 0.03

= 0.22

Using Henderson Hesselbach equation :

$pH=pK_a+\log \frac{[Salt]}{[Acid]}$

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3 years ago

A certain shade of blue has a frequency of 7.08×1014 Hz. What is the energy of exactly one photon of this light? Planck's consta

Anvisha [2.4K]

Answer:

We have the final answer as

$4.69 \times {10}^{ - 19} \: \: J$

Explanation:

To find the energy of a photon of this light we use the formula

<h3>E = hf</h3>

where

E is the energy

f is the frequency

h is the Planck's constant which is

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From the question

f = 7.08×10¹⁴ Hz

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We have the final answer as

$4.69 \times {10}^{ - 19} \: \: J$

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