What are the coordinates of point A?

The figures are similar. Find the missing length

Delicious77 [7]

Answer:

4.5 feet, or is there is 5 feet as an option, then 5 feet.

Step-by-step explanation:

ya just subtract

3 0

3 years ago

Which best explains how you know that P(2, 7) is on the same line as Q(7, 4) and R(12, 1)?

Helen [10]

Answer:

See explanation below

Step-by-step explanation:

The best explanation is noticing that in order to get from the point R (12, 1) to the point Q (7, 4) we move 5 units to the left and 3 units up. And to go from point Q (7, 4) to point P (2, 7) we do exactly the same: move 5 units to the left and 3 units up. That means that these points are all connected via the same rate of change: - 3/5, which is in fact the slope of the line the three points belong to.

4 0

3 years ago

PLEASE HELP

Elodia [21]

Answer:

The area of the resulting cross section is $78.5\ m^{2}$

Step-by-step explanation:

we know that

The resulting cross section is a circle congruent with the circle of the base of cylinder

therefore

The area is equal to

$A=\pi r^{2}$

we have

$\pi=3.14$

$r=10/2=5\ m$ -----> the radius is half the diameter

substitute the values

$A=(3.14)(5)^{2}=78.5\ m^{2}$

7 0

3 years ago

If g(x) = x+1/ x-2 and h (x) =4 - x , what is the value of ( g*h) (-3)?

Lapatulllka [165]

<u>Answer:</u>

g (h (x) ) = 5/8

<u>Step-by-step explanation:</u>

We are given the following two functions and we are to find the value of $g ( h ( - 3 ) )$ :

$g ( x ) = \frac { x + 1 } { x + 2 }$

$h ( x ) = 4 - x$

Firstly, we need to find the function :

$g ( h ( x ) ) = \frac { ( 4 - x + 1 ) } { ( 4 - x - 2 ) } = \frac { 5 - x } { 2 - x }$

Now substituting the value $x=-3$ in it:

$g ( h ( x ) ) = \frac { 5 - (-3) } { 2 - (-3) }$

g (h (x) ) = 5/8

5 0

3 years ago

hich statement best describes the domain and range of p(x) = 6–x and q(x) = 6x? p(x) and q(x) have the same domain and the same

Sati [7]

Answer:

$p(x)$ and $q(x)$ have the same domain and the same range.

Step-by-step explanation:

$p(x) = 6-x$ and

$q(x) = 6x$

First of all, let us have a look at the definition of domain and range.

Domain of a function $y =f(x)$ is the set of input value i.e. the value of $x$ for which the function $f(x)$ is defined.

Range of a function $y =f(x)$ is the set of output value i.e. the value of $y$ or $f(x)$ for the values of $x$ in the domain.

Now, let us consider the given functions one by one:

$p(x) = 6-x$

Let us sketch the graph of given function.

Please find attached graph.

There are no values of $x$ for which p(x) is not defined so domain is All real numbers.

So, domain is $(-\infty, \infty)$ or $x\in R$

Its range is also All Real Numbers

So, Range is $(-\infty, \infty)$ or $x\in R$

$q(x) = 6x$

Let us sketch the graph of given function.

Please find attached graph.

There are no values of $x$ for which $q(x)$ is not defined so domain is All real numbers.

So, domain is $(-\infty, \infty)$ or $x\in R$

Its range is also All Real Numbers

So, Range is $(-\infty, \infty)$ or $x\in R$

Hence, the correct answer is:

$p(x)$ and $q(x)$ have the same domain and the same range.

4 0

3 years ago