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blagie [28]
3 years ago
11

Y>-3x+1 How do I graph this

Mathematics
1 answer:
Brut [27]3 years ago
4 0

Answer:

<u>The graph of y>-3x+1 through the points </u><u>(0,1)</u><u> and </u><u>(1,-2)</u>

Step-by-step explanation:

y=3x+1 is in the slope intercept form

y=mx+b

m = the slope in this case 3

b = the y intercept in this case 1.

Think of b the y intercept as the beginning this is where to start the graph.

So start with (0,1) the y intercept and make the first point at (0,1)

Think of m ( the slope) as the mountain slope, This is the angle of the slope of the line

So in this case go up three on the y axis and over 1 on the x axis.

make the next point at 1 + 3 = 4 for the y value and 0 + 1 = 1 for the x value. Make the next point at ( 1, 4)

Now connect the points. creating the line

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Determine whether the graph represents a function . If it does represent a function , give its domain and range.
laiz [17]

Answer:

A function is a relationship that maps elements from a set (the domain) into elements from another set (the range)

Such that each element in the domain can be mapped into only one element from the range.

Let's see graphs 18, 20,24 and 30.

Remember that the axis that represents the domain is the horizontal one (usually represented with x), and the vertical axis represents the range (usually represented with y)

18) Here we can see that the point x = 1 his mapped into two different values of y.

we have the pair (1, 2) and the pair (1, -3)

And something similar happens for x = 2.

Then we can conclude that this is not a function.

20) Here we have a linear relationship.

Linear relationships are almost always functions, the only case when these are not functions is when the linear equation is something like x = a.

Linear equations can be written as:

y = a*x + b

So x can be any value, and thus y also can be any value.

Then the domain is the set of all real numbers, and the range is the set of all real numbers.

24) Here we have a quadratic function whose arms go down.

This is a function, now let's see the domain and range.

Quadratic functions are written as:

y = a*x^2 + b*x + c

There is no value of x can cause some problem in this equation, then this function works for all values of x, then the domain is the set of all real numbers.

Now, let's look at the graph.

We can see that the function goes up, reaches a maximum, and then goes down again.

Then the range will be the set of all the values smaller than the maximum we can see in the graph, this is:

y ∈ (-∞, 15]

or simply:

y ≤ 15.

30) Here again, we can see that for x = 0 there are two different values of y.

the same happens for x = -1, x = -2, and a lot of other values.

Then this is not a function, because it is mapping values of the domain into different values of the range.

3 0
3 years ago
Can you correctly identify this triangle?<br><br>​
yan [13]

Answer:

Isosceles triangle

Step-by-step explanation:

Any triangle whose two sides or two angles are equal is called an isoscl triangle

5 0
3 years ago
Read 2 more answers
Please help me tyy!!
iris [78.8K]

Answer:

aight so monkey monkey is monkey so if u put monkey and monkey together u get happy baby monkey did i explain myself?????

Step-by-step explanation:

4 0
2 years ago
What is the area of the largest rectangle with lower base on the x-axis and upper vertices on the curve y = 27 − x^2? show your
LUCKY_DIMON [66]

Answer:

Option B.

Step-by-step explanation:

The given curve is

y=27-x^2

We need to find the area of the largest rectangle with lower base on the x-axis and upper vertices on the curve y=27-x^2.

Let the vertex in quadrant I be (x,y), then the vertex in quadrant II is (-x,y) .

Length of the rectangle = 2x

Width of the rectangle = y

Area of a rectangle is

Area=Length\times width

Area=2x\times y

Substitute the value of y from the given equation.

Area=2x(27-x^2)

A=54x-2x^3      .... (1)

Differentiate with respect to x.

\frac{dA}{dx}=54-6x^2

Equate \frac{dA}{dx}=0, to find the critical points.

0=54-6x^2

6x^2=54

Divide both sides by 6.

x^2=9

x=\pm 3

The value of x can not be negative because side length can not be negative.

Substitute x=3 in equation (1).

A=54(3)-2(3)^3

A=162-54

A=108

The area of the largest rectangle is 108 square units.

Therefore, the correct option is B.

7 0
3 years ago
The length of each side of a square increases by 2.5 inches to form a new square with a perimeter of 70 inches. The length of ea
Lady_Fox [76]
Let x be the original side length of the square

P=2(l+w) 
70=2((2.5+x)+(2.5+x))
70=2(5+2x) 
70/2 = 5+2x 
35-5=2x
30=2x
15=x 

Therefore, the original length of the square was 15" 

Hope I helped :) 
4 0
4 years ago
Read 2 more answers
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