Answer: 30.34m/s
Explanation:
The sum of forces in the y direction 0 = N cos 28 - μN sin28 - mg
Sum of forces in the x direction
mv²/r = N sin 28 + μN cos 28
mv²/r = N(sin 28 + μcos 28)
Thus,
mv²/r = mg [(sin 28 + μ cos 28)/(cos 28 - μ sin 28)]
v²/r = g [(sin 28 + μ cos 28)/(cos 28 - μ sin 28)]
v²/36 = 9.8 [(0.4695 + 0.87*0.8829) - (0.8829 - 0.87*0.4695)]
v²/36 = 9.8 [(0.4695 + 0.7681) / (0.8829 - 0.4085)]
v²/36 = 9.8 (1.2376/0.4744)
v²/36 = 9.8 * 2.6088
v²/36 = 25.57
v² = 920.52
v = 30.34m/s
Answer:
electrons
Explanation:
The magnitude of the electric field outside an electrically charged sphere is given by the equation
where
k is the Coulomb's constant
Q is the charge stored on the sphere
r is the distance (from the centre of the sphere) at which the field is calculated
In this problem, the cloud is assumed to be a charged sphere, so we have:
is the maximum electric field strength tolerated by the air before breakdown occurs
is the radius of the sphere
Re-arranging the equation for Q, we find the maximum charge that can be stored on the cloud:
Assuming that the cloud is negatively charged, then
And since the charge of one electron is
The number of excess electrons on the cloud is
The charge of one electron is 1.6 x 10⁻¹⁹ C
Number of electrons = (50 x 10⁻⁶) / 1.6 x 10⁻¹⁹
= 3.125 x 10¹⁴ electrons
Answer:
The required torque is 1.17 N-m.
Explanation:
The given data :-
The magnitude of force ( F ) = 4.5 N.
The length of arm ( r ) = 0.26 m.
Here given that force is applied at perpendicular means ( ∅ ) = 90°.
The torque ( T ) is given by
T = F * r * sin∅
T = 4.5 * 0.26 * sin 90°
T = 4.5 * 0.26 * 1
T = 1.17 N-m.
Answer:
power=work done÷time taken
2×5=10
10÷10=1
ans 1J per second